6y > 8 - 5
6y > 3
y > 3/6
y > 1/2
Answer:
Yes
Step-by-step explanation:
Use the completing the square method:
16(x^2-x)+4
=16((x-1/2)^2 - (1/2)^2)+4
=16((x-1/2)^2 - 1/4)+4
=16((x-1/2)^2) - 16/4 + 4
=16(x-1/2)^2
=4^2(x-1/2)^2
The product of two square is itself a square.
Is the relation {(1, 3), (–4, 0), (3, 1), (0, 4), (2, 3)} a function? Why or why not? No, the range value 3 corresponds to two d
Lynna [10]
Answer:
Yes, there is no value in the domain that corresponds to ore than one value of the range. Hope I helped
In the standard form of quadratic
the discriminant is
In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.
mmcht. can't really see the graph