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Alexus [3.1K]
3 years ago
13

​Which of the following nets are true for this right rectangular prism / cuboid?

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

b

Step-by-step explanation:

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jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or,                    (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or,                    (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 209.33 yards

or,                    (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0
3 years ago
Read 2 more answers
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
What does 2 x 8/10 equal?
devlian [24]

Answer:

1.6

Step-by-step explanation:

8/10 x 2

2 divides 10

8/5

8 divided by 5=1.6

please give me branliyest

6 0
3 years ago
Help me pleaseeeeeeeee
topjm [15]

Answer:

x = 6, y = 3

Step-by-step explanation:

Let Sally's age be x and Tomas's age be y.

Sum of Sally's age plus twice Tomas's age: x + 2y = 12

Difference of Sally's age and Tomas's age: x - y = 3

Multiply the second equation by two and add it to the first equation to get

3x = 18, which means x = 6.

Plug 6 in for x in the second equation to get 6 - y = 3, which means y = 3.

7 0
3 years ago
Read 2 more answers
Y=-3x+5<br> 5x-4y=-3<br> pls help
salantis [7]

Hello!

\large\boxed{x = 1, y = 2}

We can solve this system using substitution.

Since y = -3x + 5, we can substitute this into the following equation:

5x - 4(-3x + 5) = -3

Simplify:

5x - 4(-3x) - 4(5) = -3

5x + 12x - 20 = -3

Combine like terms:

17x - 20 = -3

Add 20 to both sides:

17x = 17

x = 1

Substitute to find y:

y = -3(1) + 5

y = -3 + 5

y = 2

Solution: (1, 2)

7 0
2 years ago
Read 2 more answers
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