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Brilliant_brown [7]
3 years ago
5

Please I need help asap!

Mathematics
1 answer:
Darya [45]3 years ago
3 0
The path between the two houses and the path the homing pigeon will fly form a triangle. (Shown in picture)

To solve this problem you are finding the hypotenuse of the triangle. This can be solved using the Pythagorean theorem: a^2 + b^2 = c^2

Start by identifying your variables:
a: 6 (miles north)
b: 8 (miles west)
c: miles of the homing pigeon’s path

After identifying your variables, substitute the values into your equation.
This results in:
6^2 + 8^2 = c^2

Next, square both of your a and b values by multiplying each value by temselves. 6 x 6 is 36 and 8 x 8 is 64
So...
This leaves you with:
36 + 64 = c^2

After that, add your values together to get one value on each side of the equal sign.
36 + 64 = 100
This leaves you with 100 = c^2

To find your final answer, square root both sides to isolate and solve for the c value.
The square root of 100 is 10.

So your final answer is 10 miles.
The homing pigeon will fly 10 miles between Joe and Raul’s houses.
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Answer:

35

Step-by-step explanation:

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6 0
2 years ago
Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

lim_{x\rightarrow 2^-}f(x)=6

lim_{x\rightarrow 2^+}f(x)=-3

6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0
3 years ago
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