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3 years ago

Write a rule for the linear function with the following description: the graph contains the points (3,-2) and (3,0),

Mathematics

1 answer:

Maslowich3 years ago

3 0

Answer:

x - 3 = 0

Step-by-step explanation:

You can realise it plotting the points.

Or you can use : ( x - x1 ) / ( y - y1 ) = ( x1 - x2 ) / ( y1 - y2 )

where ( x1 , y1 ) and ( x2 , y2 ) are the given points.

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Solve the formula A=10+ry. solve for y

noname [10]

The given formula $A= 10 + ry$

Solve for y means we have to make y alone

$A= 10 + ry$ \\

Add -10 on both sides, we get

$A - 10 = 10 -10 + ry \\A - 10 = 0 + ryA - 10 = ry$

As there is multiplication sign between r and y so to solve for y, divide both side by r

$\frac{A - 10}{r} = y\\\\y = \frac{A - 10}{r}$

4 0

3 years ago

Read 2 more answers

Can someone please help me with this!!!

Yanka [14]

4mins---->12 cars
6mins---->(6*12/4)=18

4mins---->12
5mins---->(5*12/4)=15

And so on

6 0

3 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

5 0

3 years ago

Factor the trinomial x^2 - 2x - 8

ValentinkaMS [17]

Well what two numbers multiply to get -8 and add to get -2?
Well, to get -8, we either have (-1,8),(-2,4),(-4,2),(-8,1)
8-1=7
-2+4=2
2-4=-2
1-8=-7
Thus it should be (-4,2),
This means we should get (X-4)(X+2)

7 0

3 years ago

What is the surface area of the right trapezoidal prism? To receive credit, you must show the work used to arrive at a final ans

julia-pushkina [17]

Answer:

210 cm²

Step-by-step explanation:

The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.

Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles

✔️Area of the 2 trapezoid bases:

Area = 2(½(a + b)×h)

Where,

a = 7 cm

b = 11 cm

h = 3 cm

Plug in the values

Area = 2(½(7 + 11)×3)

= (18 × 3)

Area of the 2 trapezoid bases = 54 cm²

✔️Area of Rectangle 1:

Length = 6 cm

Width = 3 cm

Area = 6 × 3 = 18 cm²

✔️Area of Rectangle 2:

Length = 7 cm

Width = 6 cm

Area = 7 × 6 = 42 cm²

✔️Area of Rectangle 3:

Length = 6 cm

Width = 5 cm

Area = 6 × 5 = 30 cm²

✔️Area of Rectangle 4:

Length = 11 cm

Width = 6 cm

Area = 11 × 6 = 66 cm²

✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²

7 0

2 years ago