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3 years ago

M/J Grade 8 Pre-Algebra-PT-FL-1205070-003

Mathematics

1 answer:

Andreas93 [3]3 years ago

5 0

Answer:

Following are the description of the given course code:

Step-by-step explanation:

The given course code is Pre-Algebra, which is just an introduction arithmetic course programs to train high school in the Algebra 1. This course aims to strengthen required problem solving skills, datatypes, equations, as well as graphing.

In this course students start to see the "big picture" of maths but also understand that mathematical, algorithmic, and angular principles are intertwined to form a basis for higher mathematics education.
The duration of this code is in year and it is divided into two levels. In this, code it includes PreK to 12 Education Courses , with the general mathematics .

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A plumbing company charges an initial fee of $50, plus an additional $26 per hour of service. A second company charges an initia

torisob [31]

The answer is C. You pay $128 in the third hour for both. Hope this helped

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2 years ago

Solve each system by substitution 5x + 7y = -23 Y = -2x - 11

Alenkasestr [34]

Answer:

x = −6

Explanation:

5x + 7y = -23

Y = -2x - 11

Substitute -2x - 11 for y in 5x + 7y = -23

5x + 7(−2x − 11) = −23

Simplify both sides of the equation

5x + 7(−2x − 11) = −23

5x + (7)(−2x ) + (7)(−11) = −23 (Distribute)

5x + −14x + −77 = −23

(5x + −14x) + (−77) = −23 (Combine Like Terms)

−9x + −77 = −23

−9x − 77 = −23

Add 77 to both sides

−9x − 77 + 77 = −23 + 77

−9x = 54

Divide both sides by -9

−9x / -9 = 54 / -9

x = -6

6 0

3 years ago

PLEASE HELPPPP!!!!!!!!!!!!

sladkih [1.3K]

Given:

Two endpoints of a diameter of a circle:

P (-7, -10)
Q (3, 2)

a) To find the center of the circle, find the midpoint of the two points:

midpoint:

(x2 - x1 )/ 2 , (y2 - y1) / 2

x= (2 - (-7))/2 = 4.5
y= (3 - (-10))/2 = 6.5

Therefore, the center of the circle is at C(4.5, 6.5)

b) To find the radius of the circle, we need to find the distance between the two points and divide by 2.

d = √(y2-y1)^2 + (x2 - x1)^2
d = √(2-(-7))^2 + (3 - (-10))^2
d = 5√10 = diameter
r = d/2 = 5√10 /2

5 0

3 years ago

Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. The length of the yard is 8 feet

Rufina [12.5K]

Please check the attached file for the diagram of Sally's yard.

Let $w$ be the width of the yard.

Let $l$ be the length.

We are given that the length of the yard is 8 feet more than 4 times the width. Let us convert this into a mathematical equation.

4 times the width will be $4w$ . Now, 8 feet, or 8 more than 4 times the width will be $4w+8$ . We know that this is the value of the length of the yard and thus we can write this as:

$l=4w+8$

As we can see we have found the relationship between the length, $l$ and the width, $w$ of the yard.

We have been told that the total length of the fence required for the yard is 106 feet. This obviously means that the perimeter of the rectangular yard is 106 feet.

Now, we know that the perimeter of a rectangle is given by:

Perimeter= $2(l+w)=2((4w+8)+w)$ this is because we know that the length, $l$ is given by $l=4w+8$ .

Continuing further we get:

$106=8w+16+2w=10w+16$ This is because Perimeter=length of the fence=106 (given)

Therefore, $10w=90$

or, $w=9$ so, we just now found the width of the yard which is 9 feet. We are required to find the length. We can easily find the length using the relationship between $w$ and $l$ which is:

$l=4w+8$ giving us:

$l=4\times9+8=44$

Thus the length of the fence is 44 feet.

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3 years ago

Graph the function y = |1.6x – 2| – 3.2. Over which interval is the function increasing?

klasskru [66]

You are to graph y = |1.6x – 2| – 3.2. I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).

Let's rewrite y = |1.6x – 2| – 3.2 by factoring 1.6 out of |1.6x - 2|:

y = 1.6*|x – 2/1.6| – 3.2

This tells us that the vertex of y = |1.6x – 2| – 3.2 is at (2/1.6, -3.2). If you need an explanation of why this is, please ask.

Plot the vertex at (1.25, -3.2).
Find the y-intercept: Let x = 0 in y = |1.6x – 2| – 3.2 and find y:

y = 2-3.2 = -1.2

The y-intercept is located at 0, -1.2)

Plot this y-intercept.

Now draw a straight line from the vertex to this y-intercept. Reflect that line across the y-axis to obtain the other half of the graph.

8 0

3 years ago

Read 2 more answers