Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
Answer:
Make N alone
There is an 8 so we subtract 8 from both sides so the equation is still equal
-4 - 8 = -12
Because we are subtracting N it is positive
N = 12
8 - 12 = -4
Hope this helps
Step-by-step explanation:
<span>A 20° sector in a circle has an area of 21.5π yd²</span>
It is not A. because 8 is not a prime number.
It is not B. because 12 is not a prime number.
C. 2 x 2 x 2 x 2 x 2 x 3 = 4*4*6= 96
D. 2 x 2 x 2 x 2 x 2 x 3 x 3= 4*4*6*3=16*18= 288
Answer is C. -2 x 2 x 2 x 2 x 2 x 3 : 96 ( not D. = 298 , 298 is greater than 96)
The feasible region is shown in the picture above. The horizontal axis is the X axis.
If you now draw a family of lines parallel to 
through the region, increasing $C$, that is, the X-intercept, we will have the maximum value of $C$ when the line passes through the endpoint $(-2,6)$ .
Hence, $C=5(-2)+4(6)=14$
