You have to use these facts:
1) The derivative of a sum is the sum of the derivatives
2) d[x^n] / dx = n x ^ (n - 1)
3) d [a(f(x) ] / dx = a d [f(x)] / dx
=> d [x^3 + 3x^2 + 5] / dx = d[x^3]/dx + 3d[x^2]/dx + 0
= 3x^2 + 6x
Answer: option D. 3x^2 + 6x
Answer:
Not enough information is given to help I'm Sorry
Step-by-step explanation:
Firs month A
Second month 3A
Third month 3*3A = A (3^2)
Fourth month A(3^3)
Fith month A (3^4)
nth month A (3 ^ (n-1) )
That is an exponential model, because the variable (time, n) is the exponent of the formula.
Answer:
D
Step-by-step explanation:
8^2+x^2=16^2
