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aev [14]
2 years ago
7

What is the domain of f(x)=square root of 9-14x

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer: 6.9

Step-by-step explanation:

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What is 4 - ( -h ) = 68?
Kryger [21]
4 + h = 68

h = 68 - 4

h = 64

hope this helps
5 0
3 years ago
Read 2 more answers
Expand each expression and collect like terms -3(2p-3q)
sertanlavr [38]

Answer

(-3 * 2p) - (-3 * 3q)

Step-by-step explanation:

I dunno how to explain it but that's it

7 0
2 years ago
Jared bought a Suzuki 1000 for $12,698. If it depreciates at a rate of 11% per year, how much will it be worth in 3 years
Serga [27]
Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
New price = A

The formula used will be:

A=P(1-r)^{t}

Using the values, we get:

A=12698(1-0.11)^{3}=8951.70

Thus, the worth of Suzuki after 3 years will be $8951.70
7 0
3 years ago
HELP i’m having trouble with my homework assignments
Aleksandr-060686 [28]

Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

In Collin's case, we have ...

P0 = 55,000, t = 43, d = 15

so his salary at retirement is ...

P(43) = $55,000(2^(43/15)) ≈ $401,157.89

In Cameron's case, we have ...

P0 = 35,000, t = 43, d = 10

so his salary at retirement is ...

P(43) = $35,000(2^(43/10)) ≈ $689,440.87

___

Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

(1/d)ln(2) = k . . . . . take the natural log of both sides

So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

5 0
3 years ago
Presents of equal size are in a boxes each with dimensions of 10 inches length, 4 inches width, and 2 inches height. How many pr
Maurinko [17]

Answer:

You can make 7.5 gifts presents (or just 7)

Step-by-step explanation:

First I calculated the area of 1 box, which is 80 inches squared. Then I just divided the 600 square inches with the 80 inches. 600/80= 7.5. Therefore, you can make 7 presents (since you cannot wrap half of a present (0.5))

Hope this helps !

4 0
2 years ago
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