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3 years ago

What will happen to the size of the population in the long run?

1 answer:

7 0

I'm assuming there's a chart, but if there isn't,

The population will continue to increase and decrease, as the population will grow until it's reached its carrying capacity, and then decrease because there aren't enough resources, and then increase, then decrease, etc.

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Divide £250 to ratio 3:6:1

fiasKO [112]

Answer --> 75 : 150 : 25

3/10 x 250 = 75
6/10 x 250 = 150
1/10 x 250 = 25

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3 years ago

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What is -11/8 + -11/4

madam [21]

Answer:

-4and1/8

Step-by-step explanation:math

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3 years ago

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DIAGRAM IN PICTURE

12345 [234]

Answer:

4.472

Step-by-step explanation:

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3 years ago

1. Ramon spends 2/5 of his monthly income on rent, 1/5 of his monthly income on utilities, and 3/4 of the amount remaining on fo

hichkok12 [17]

If x is how much his income is then 2/5x+1/5x= 3/5x for rent and utilities. x-3/5x=2/5x leftover. 3/4×2/5x=3/10x for food. 3/5x+3/10x=9/10x spent on rent, utilities, and food and rec. He saves the rest which is x-9/10x= 1/10x so if 1/10x=193.50
x= $1,935 for his income

7 0

3 years ago

Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

I'm going to use $x$ instead of $\theta$ because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

$\cot(x)+\cot(\frac{\pi}{2}-x)$

I'm going to use a cofunction identity for the 2nd term.

This is the identity: $\tan(x)=\cot(\frac{\pi}{2}-x)$ I'm going to use there.

$\cot(x)+\tan(x)$

I'm going to rewrite this in terms of $\sin(x)$ and $\cos(x)$ because I prefer to work in those terms. My objective here is to some how write this sum as a product.