4 years ago

PLEASE HELP!!

Mathematics

1 answer:

Montano1993 [528]4 years ago

7 0

Your method is right so u already know how to do it

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photoshop1234 [79]

Substitute $u=x^2+4$ and $du=2x\,dx$ . Then the integral transforms to

$\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \int \frac{du}{u^3}$

Apply the power rule.

$\displaystyle \int \frac{du}{u^3} = -\dfrac1{2u^2} + C$

Now put the result back in terms of $x$ .

$\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \left(-\dfrac1{2u^2} + C\right) = -\dfrac1{4u^2} + C = \boxed{-\dfrac1{4(x^2+4)^2} + C}$

3 0

2 years ago

Can anyone help me with this math question? I don’t quite understand, I hope everyone has a great day!

Ivenika [448]

Maya has 14 stickers her friend is going to give her somemore for her birthday 14+A

3 0

3 years ago

Find the area of the figure.

Contact [7]

area of rectangle= 8*13=104m^2

base of the Triangle= 13 -(4+4)=5

area of Triangle = 5*6/2=15m^2

area of shaded shape =104-15= 89m^2

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3 years ago

If y varies inversely as x and y is 2.5 when x is 6, what is y when x is 4? a. 3.75 b. 1.67 c. 0.1 d. 7.5 Please select the best

REY [17]

Because y varies inversely as x, therefore
$y= \frac{k}{x}$
where k = constant.

When x = 6, y = 2.5. Ther efore
$\frac{k}{6} = 2.5$
Cross multiply.
k = 6 x 2.5 = 15

The equation is
$y = \frac{15}{x}$

When x = 4, obtain
$y = \frac{15}{4}= 3.75$

Answer: a. 3.75

8 0

3 years ago

Read 2 more answers

Brandon graphed one line in a system of equations. The system has only one solution, (0,3). Which equations could also be part o

AlladinOne [14]

Answer:

y = 3 and y = x + 3

Step-by-step explanation:

The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.

Consider the equation y = x + 3.

Substitute (0, 3).

3 = 0 + 3

So, (0, 3) lies on y = x + 3 and this can also be a part of the system.

6 0

3 years ago

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