Please help me thank you. :)

Describe a normal probability distribution. a. bell-shaped.b. mean, median, and mode all equivalent.c. bimodal.d. symmetric arou

garri49 [273]

Answer:

a) bell-shaped.

b) mean, median, and mode all equivalent.

d) symmetric around the mean.

g) most of the data fall within 3 standard deviations from the mean.

Step-by-step explanation:

We have to describe a normal distribution.

a. bell-shaped.

This is true a normal distribution is a bell shaped distribution.

b. mean, median, and mode all equivalent.

This is true for a normal distribution.

Mean = Mode = Median

c. Bimodal

The is not true about the normal distribution. A normal distribution is unimodal and the mode is equal to the mean of the distribution.

d. symmetric around the mean.

This is true. The normal distribution is centered around the mean

e. skewed to the right.

This is not a property of normal distribution.

f. models discrete random variables.

Normal distribution is a continuous distribution.

g. most of the data fall within 3 standard deviations from the mean.

This is true. According to Empirical rule, almost all the data lies within three standard deviation of mean.

h. uniform-shaped

This is not true. A normal distribution is bell shaped.

4 0

3 years ago

Can someone please help me find the side length area, and please draw the shape on how it would look if it were finished

Mumz [18]

The side length is 5 units, and the area is 25 square units

<h3>What are areas?</h3>

The area of a shape is the amount of space it occupies

<h3>What is the area of a square</h3>

The area of a square is the product of its dimensions

From the graph, the coordinates of the square can be assumed to be:

$A = (0,0)$

$B = (4,3)$

The side length of the square is then calculated using the following distance formula

$d = \sqrt{(x_2- x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$AB = \sqrt{(0 - 4)^2 + (0-3)^2}$

$AB = \sqrt{25}$

$AB = 5$

The area of the square is the calculated as:

$Area = AB^2$

This gives

$Area = 5^2$

$Area = 25$

Hence, the side length is 5 units, and the area is 25 square units

See attachment for the diagram of the shape

Read more about areas at:

brainly.com/question/24487155

6 0

2 years ago

a survey survey asked 200 students to name their favorite fruit the table shows the results of a survey

stiv31 [10]

Part A

Fraction of peach 2/5

Total = 200

number of students that pick peach as their favorite fruits

$\begin{gathered} =\text{ }\frac{2}{5}\text{ x 200} \\ =\text{ }\frac{2\text{ x 200}}{5} \\ =\text{ }\frac{400}{5} \\ =\text{ 80 students} \end{gathered}$

Part B

number of students that pick orange as their favorite fruits

$\begin{gathered} =\frac{3}{8}\times200^{} \\ =\text{ }\frac{3\text{ x 200}}{8} \\ =\text{ }\frac{600}{8} \\ =\text{ 75} \end{gathered}$

number of students that pick plum as their favorite fruits

$\begin{gathered} =\text{ }\frac{1}{10}\text{ x 200} \\ =\text{ }\frac{200}{10} \\ =\text{ 20} \end{gathered}$

There are 55 more students that chose orange rather than plum.

4 0

9 months ago

Solve for x: x^2-2x=15

Lyrx [107]

Answer:

Step-by-step explanation:

x^2 - 2x = 15

x^2 - 2x - 15 = 15 - 15 (Subtract 15 from both sides.)

x^2 - 2x -15 = 0 (Simplify.)

<em />

<em>Set up & solve for a quadratic formula</em>

<h3><em>* I will solve for your first x</em></h3>

2 + root 64 / 2x 1 = 2 + root 64 / 2

root 64 = 8

= 2 + 8 / 2

= 10 / 2

= 5

<em>To solve for the second, follow the same pattern/formula for the first that I used to get 5.</em>

5 0

3 years ago

HOW DO I FIND THE PERIMETER OF A SEMICIRCLE WITH A RADIUS OF 9MM ?

dybincka [34]

Perimeter = 2 × π × r

Perimeter = 2 × 3.14 × 9

Perimeter = 56.52

Perimeter = 56.52 ÷ 2

Perimeter = 28.26

The perimeter of a semicircle with a radius of 9mm is 28.26

6 0

3 years ago

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