Question

Jalen has $10.35 in quarters and nickels he has a total of 99 coins how many of each coins does he have?

Answer 1

Answers:

72 nickels and 27 quarters

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Work Shown:

$10.35 = 1035 cents

q = number of quarters

n = number of nickels

n+q = 99 is the total number of coins. This solves to q = -n+99

25q = value of all the quarters in cents

5n = value of all the nickels in cents

5n+25q = 1035 is the total value in cents

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5n+25q = 1035

5n+25( q ) = 1035

5n+25( -n+99 ) = 1035

5n - 25n + 2475 = 1035

-20n + 2475 = 1035

-20n = 1035-2475

-20n = -1440

n = -1440/(-20)

n = 72

Jalen has 72 nickels

q = -n+99

q = -72+99

q = 27

Jalen has 27 quarters

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Check:

n+q = 72+27 = 99

5n+25q = 5*72+25*27 = 1035

This confirms the answers.