Jalen has $10.35 in quarters and nickels he has a total of 99 coins how many of each coins does he have?
1 answer:
Answers:
72 nickels and 27 quarters
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Work Shown:
$10.35 = 1035 cents
q = number of quarters
n = number of nickels
n+q = 99 is the total number of coins. This solves to q = -n+99
25q = value of all the quarters in cents
5n = value of all the nickels in cents
5n+25q = 1035 is the total value in cents
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5n+25q = 1035
5n+25( q ) = 1035
5n+25( -n+99 ) = 1035
5n - 25n + 2475 = 1035
-20n + 2475 = 1035
-20n = 1035-2475
-20n = -1440
n = -1440/(-20)
n = 72
Jalen has 72 nickels
q = -n+99
q = -72+99
q = 27
Jalen has 27 quarters
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Check:
n+q = 72+27 = 99
5n+25q = 5*72+25*27 = 1035
This confirms the answers.
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