Answer:
Divide: 2 : 1
8
= 2
1
· 8
1
= 2 · 8
1 · 1
= 16
1
= 16
Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 1
8
is 8
1
) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.
In words - two divided by one eighth = sixteen.
SO FINAL ANSWER IS 16!!! HOPE THIS HELPS YOU mark me the brainliest if im correct
3(6x+2) <9
Use distributive property:
18x + 6 < 9
Subtract 6 from both sides
18x < 3
Divide both sides by 18
X < 3/18
Simplify:
X < 1/6
<em>The question has inconsistent or incomplete data, so I'm filling the holes with key data.</em>
Answer:
<em>Every people at dinner received one-tenth of the original turkey= 0.1</em>
Step-by-step explanation:
<u>Proportions</u>
If some fraction a/b of a whole total M is to be computed and later removed, we proceed as follows
* Compute the portion to be removed as a/b*M
* Subtract it from the total quantity: M-a/b*M=M(1-a/b)
I'm assuming 1/5 of the turkey was lost due to overcooking. It means that (1-1/5) of the turkey remained for dinner, that is, 4/5 of the turkey.
Each people at dinner received the same amount of the remaining, so we must divide 4/5 by 8, to get 4/40, or 1/10. It means that every people at dinner received one-tenth of the original turkey
Answer:
There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).
The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).