Answer:
Alicia is 18years
Quentin is 14years
Rosalyn is 16years
Step-by-step explanation:
Let the age of Alicia be x
Let the age of Quentin be y
Let the age of Rosalyn be z
If the sum of the siblings’ ages, in years, is 48 then;
x+y+z = 48.... 1
If Rosalyn is two years older than Quentin then;
z =y+2 ..... 2
Also if Quentin is four years younger than Alicia then;
y = x-4 ... 3
From 3:
x = y+4 ... 4
Substitute 2 and 4 into 1 to have:
y+4+y+y+2 = 48
3y + 6= 48
3y = 48-6
3y= 42
y = 14
Since x= y+4
x = 14+4
x = 18
Since z = y+2
z = 14+2
z = 16year
This means that;
Alicia is 18years
Quentin is 14years
Rosalyn is 16years
I know m=2.25 and n=8.6 but I don't know about q.
No, 2 of the 5x7 would actually take up. 10x14
Answer:
b≤3
Step-by-step explanation:
For this problem, you want to solve it similarly to linear equations.
We start with 4b+6≤18.
Subtracting 6 from both sides gives 4b≤12.
From there, in order to isolate the b, we must divide both sides by 4, leaving b≤3.
**This content involves solving linear inequalities, which you may wish to revise. I'm always happy to help!
Answer:
189.98
Step-by-step explanation:
