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Ilia_Sergeevich [38]
3 years ago
11

Help me answer this.. plz

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

2\frac{1}{30}

Step-by-step explanation:

First thing you gotta do is find the common denominator.

Do this by listing factors of the denominators:

5- 5, 10, 15, 20, 25, 30

6- 6, 12, 18, 24, 30, 36

5 and 6 both have 30 in common so that's the new denominator for all 3 of the terms.

What you do to the bottom you must do to the top.

Since you multiply 5 by 6 to get 30, you must multiply 2 and 4 by 6 as well.

Since you multiply 6 by 5 to get 30, then multiply 5 by 5 as well.

The new equation is:

\frac{12}{30} +\frac{25}{30} + \frac{24}{30} =

Now add the numerators together

The solution is \frac{61}{30}. Now simplify. 61 is prime, so you cannot change the fraction How many times does 30 go into 61? Two times. This gives us 2\frac{1}{30}.

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200 meters
Katyanochek1 [597]

Answer:

520 m

Step-by-step explanation:

Perimeter is the distance around a shape. To find the perimeter, you add up all the sides.

200 + 60 + 60 + 200 = 520 m

7 0
3 years ago
Find the sum 1/6 (12C + 24) + 1/3(12- 3)<br><br>a-b-c- or d
Anarel [89]
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3 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

3 0
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