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3 years ago

8

Luke can build 2 tables in a day, and he has to build more than 18 wooden tables for a client. If he works for x days, what is t

he simplest inequality that represents this situation?

1 answer:

VARVARA [1.3K]3 years ago

6 0

2x > 18

2x/2 > 18/2

X > 9

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the price of a gallon of unleaded gas was $2.86 yesterday. today, the price fell to $2.79. find the percent decrease. round answ

soldier1979 [14.2K]

So.. 2.86 - 2.79 is the amount in decrease or 0.07

so.. if we take 2.86 as the 100%, how much is 0.07 of that in percentage?

well $\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
2.86&100\\
0.07&x
\end{array}\implies \cfrac{2.86}{0.07}=\cfrac{100}{x}$

solve for "x"

3 0

2 years ago

PLEASE HELP ILL MARK U BRAINLIEST!!!!!!!

stiks02 [169]

Answer:

$7 dollar per adult

$4 dollars per child

two adults and two children would cost $22

Step-by-step explanation:

6 0

2 years ago

The time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a

leva [86]

Answer:

Step-by-step explanation:

Given that X the time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.

We have 68 rule as 2/3 of total would lie within 1 std deviation, and 95 rule as nearly 95% lie within 2 std deviations from the mean.

We have std deviation = 10

Hence 2 std deviations from the mean

= Mean ±2 std deviations

= $70$ ±20

= $(50,90)$

Below 50, 0.25 or 2.5% would complete the exam.

3 0

3 years ago

Use distributive property to rewrite 10(5+14-3)

Allisa [31]

(10x5)+(10x14)+(10x-3)
50+140-30
160

7 0

3 years ago

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

2 years ago