Scott invests $1000 at a bank that offers 6% compounded annually. Write an equation to model the growth of the investment.
2 answers:
Answer:
Step-by-step explanation:
D
Answer:You can use A=P(1+(r/n))^(nt)
n=homany times it is compounded a year: 1 annually
t=time in years
r=rate: 6% or .06
A=Final Amount
P=principle amount
A=1000(1+(.06/1))^(1*t)
Step-by-step explanation:
hope this is correct
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0 solutions
Answer:
40,885,048
Step-by-step explanation:
first find 3^12 and then find 7^9.
3^12 = 531,441
7^9 = 40,353,607
Add these together and you'll get 40,885,048.
Welcome! Hope this helps.
Answer:
3.5
Step-by-step explanation:
98/8=12.25
√12.25=3.5
