Scott invests $1000 at a bank that offers 6% compounded annually. Write an equation to model the growth of the investment.
2 answers:
Answer:
Step-by-step explanation:
D
Answer:You can use A=P(1+(r/n))^(nt)
n=homany times it is compounded a year: 1 annually
t=time in years
r=rate: 6% or .06
A=Final Amount
P=principle amount
A=1000(1+(.06/1))^(1*t)
Step-by-step explanation:
hope this is correct
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Answer:
B.-4x^2-2x+6.
Step-by-step explanation:
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=2x^2-6x^2+4x-6x+9-3.
=-4x^2-2x+6.
613 Step-by-step explanation:
2=-3(5)+b. First, you isolate the variable 2-3(5)=b. Then you solve 2-3(5)=2-15=-13. So -13=b