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svetoff [14.1K]
3 years ago
6

What is the distance between-5 and 3

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

Answer: 8

Step-by-step explanation: count with your fingers from -5 to 3

sleet_krkn [62]3 years ago
4 0
The distance between -5 and 3 is 7 units
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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
GCF of 9x^2y^2 and 5x^2y^3
8090 [49]

Answer:

x^2y^2.

Step-by-step explanation:

5 0
3 years ago
Katie gives Maggie half of her pencils. Maggie keeps 5 pencils and gives the rest to Jamil. A. Write an expression for the numbe
Alexandra [31]

Here's what I mean when I write <em>x/</em><em>2</em><em> </em><em>JUST </em><em>IN </em><em>CASE.</em>

а.

Let the total number of pencils be x, then this implies that Maggie received <em>x/</em>2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means

that Jamil receives

<em>x/</em>2-5 pencils.

b. Expression of pencils given to Jamil is: <em>x/</em>2-5

Substitute <em>x</em><em>=</em><em>1</em><em>6</em><em> </em>in this expression: <em>x/</em>2-5

Simplify and evaluate: = 8-5= 3

Maggie gives 3 pencils to Jamil.

c. Expression of pencils given to Jamil is: x/2-5 to

Equate this expression with 1 to form an equation and solve for <em>x</em> all, the total

number of pencils if Jamil received 1 pencil:

<em>x/</em>2 - 5 = 1

Solve for x:

<em>x</em> = 2(1+ 5)

Evaluate:

<em>x</em> = 2(6) = 12

Katie had 12 pencils if Jamil received 1 pencil.

RESULT

a. Expression of number of pencils given to Jamil is <em>x</em>/2-5, where x is total number of pencils.

b. Maggie gives 3 pencils to Jamil.

c. Katie had 12 pencils if Jamil received 1 pencil.

5 0
3 years ago
Regina brought 8 7/8 pound of fruit for her family . She brought 3 1/2 pound of oranges and 2 3/4 pound of peaches and some appl
butalik [34]

Answer:

Regina has bought 2\frac{5}{8}\ pounds of apples.

Step-by-step explanation:

Given:

Amount of fruit brought = 8\frac{7}{8}\ pounds

Now given number is in mixed fraction we will convert into improper fraction.

To convert a mixed fraction to an improper fraction, we will Multiply the whole number part by the fraction's denominator.  Add that to the numerator,Then write the result on top of the denominator.

So we can say that;

8\frac{7}{8}\ pounds can be Rewritten as \frac{71}{8}\ pounds

Amount of fruit brought = \frac{71}{8}\ pounds

Also given:

Amount of oranges bought = 3\frac12\ pounds

3\frac12\ pounds can be Rewritten as \frac{7}{2}\ pounds

Amount of oranges bought =  \frac{7}{2}\ pounds

Amount of peaches bought = 2 \frac34\ pounds

2 \frac34\ pounds can be Rewritten as \frac{11}{4}\ pounds

Amount of peaches bought =  \frac{11}{4}\ pounds

We need to find amount of apples bought by Regina.

Solution:

Let the amount of apples bought be 'x'

Now we know that;

Amount of fruit brought is equal to sum of Amount of oranges bought and Amount of peaches bought amount of apples.

framing in equation form we get;

\frac{71}{8}=\frac{7}{2}+\frac{11}{4}+x\\\\x=\frac{71}{8}-\frac{7}{2}-\frac{11}{4}

Now we will make the denominator common using LCM we get.

x=\frac{71\times 1}{8\times 1}-\frac{7\times4}{2\times4}-\frac{11\times2}{4\times2}\\\\x=\frac{71}{8}-\frac{28}{8}-\frac{22}{8}

Now denominators are same so we will solve the numerator.

x=\frac{71-28-22}{8}\\\\x=\frac{21}{8}\ pounds

Now \frac{21}{8}\ pounds can be Rewritten as 2\frac{5}{8}\ pounds

Hence Regina has bought 2\frac{5}{8}\ pounds of apples.

5 0
3 years ago
5/7 times 4/5=? in simplest form
lys-0071 [83]
5/7 * 4/5 = 20/35 = 4/7
7 0
3 years ago
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