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SVETLANKA909090 [29]
1 year ago
8

A conduit of circular cross section has 7 cables all same diameter. Inside diameter of conduit is 30cm. What is the cross sectio

nal area of the conduit not part of the 7 cables
Mathematics
1 answer:
-BARSIC- [3]1 year ago
3 0

The cross sectional area of the conduit not part of the 7 cables is; 706.5cm²

<h3>What is the cross sectional area of the conduit not part of the 7 cables?</h3>

It follows from the task content that the conduit in discuss has 7 cables all same diameter and has a circular cross section.

Since, the cross sectional area of the conduit not part of the 7 cables is required; it follows that the cross sectional area of the inside cavity can be evaluated as follows;

where radius, r = D/2 = 30/2.

Area = πr² = 3.14 × (30/2)² = 706.5cm²

Read more on area of circular cross section;

brainly.com/question/16566008

#SPJ1

You might be interested in
In a right triangle, the hypotenuse is three inches more than twice the length of one leg. If the other leg is 12 inches, what i
andrew-mc [135]

Answer:

Length of hypothenuse = 13 inches

Length of other leg = 5 inches

Step-by-step explanation:

A triangle has three sides and three angles. A right angle triangle has 90 degrees as one of the angles. The remaining two angles are complimentary. This means that the sum if the other two angles is 90 degrees.

The longest side is the hypotenuse. The shorter sides are the opposite and adjacent.

In this triangle, the hypotenuse is three inches more than twice the length of one leg. Let the length of one leg be x inches.

Hypothenuse = 2x + 3

The other leg is 12 inches.

The diagram is illustrated in the attached photo.

Applying Pythagoras theorem,

Hypothenuse ^2 = adjacent^2 + opposite ^2

(2x+3)^2 = 12^2 + x^2

(2x+3)(2x+3)= 144 + x^2

4x^2 + 6x + 6x + 9 = 144 + x^2

4x^2 - x^2 + 6x + 6x + 9 - 144 = 0

3x^2 +12x - 135 = 0

3x^2 +27x - 15x - 135 = 0

3x(x+9)-15(x+9)=0

(3x -15)(x+9) = 0

3x -15 = 0 or x+9= 0

3x = 15 or x = -9

x = 15/3 = 5

x = 5inches because it cannot be negative.

Length of hypothenuse = 2x + 3

= 2×5 + 3 = 10 + 3 = 13 inches

6 0
3 years ago
A rectangle is inscribed in a right isosceles triangle, such that two of its vertices lie on the hypotenuse, and two other on th
Ronch [10]
Refer to the attachment for the diagram of the problem.

Let us call the two identical sides of the isosceles triangle with s. Since we know that the hypotenuse measures 45 inches, we can find s by using the Pythagorean Theorem:
45^{2} = s^{2}+ s^{2}
45^{2} = 2s^{2}
45^{2} = 2s^{2}
1012.5 = s^{2}
s=31.82

We can notice that the figure will have similar triangles with the smaller triangle having one length equal to 5x. We then compute for the equivalent hypotenuse of the smaller triangle (denoted as y).
\frac{31.82}{5x} = \frac{45}{y}
y=7.07x

We can then solve for the value of x by applying the Pythagorean Theorem in the smaller triangle.
(7.07x)^{2} = (5x)^{2}+ (31.82-2x)^{2}
50x^{2} = 25x^{2}+ 1012.5-127.28x+4x^{2}
0= -21x^{2}-127.28x+1012.5
x=4.55,-10.61

We ignore the negative value since there is no negative side. x is therefore 4.55 thus the dimensions of the rectangle would be 22.75 and 9.1. For the other case, the dimensions would simply be inverted since we would be dealing with a rectangle with its width longer than its length.

6 0
3 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
2 years ago
2d + 7 = 9<br><br>please help me!<br><br><br><br> ​
jasenka [17]

Answer:

d=1

Step-by-step explanation:

8 0
3 years ago
EASY MATH!!! GIVING BRAINLIEST!!
musickatia [10]

Answer:

55

Step-by-step explanation:

So lets take our 50 dollars.

Next, take your increase of 5%. Remember, 5% is 0.05, and it is a increase of 5%, so we are multipling 50 by 1.05.

Before we start multiplying, lets recall that this occurs twice(2 years), but this doesnt mean we multiply 50 by 1.10. No, we just mutiply 50 by 1.05 2 times:

50*1.05

=

52.5

52.5*1.05

=

55.25

So your answer is 55 dollars(rounding down).

Hope this helps!

4 0
2 years ago
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