3 years ago

Find real solutions x-(4-8x)^0.5=0

Mathematics

1 answer:

Vadim26 [7]3 years ago

5 0

Answer:

There are no real roots for this equation.

Step-by-step explanation:

The only solution is irrational: x-√(4-8x)=0

I have provided a graph to help you with this problem.

Hope this helps! :)

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Consider the quadratic function f(x) = –2x2 5x – 4. the leading coefficient of the function is?

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Answer:

$\text{-2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

Step-by-step explanation:

Given the quadratic function

$f(x)=-2x^2+5x-4$

we have to find the leading coefficient of given quadratic equation.

$\text{The general form of quadratic equation is }ax^2+bx+c=0$

The coefficient of $x^2$ i.e a is known as the leading coefficient.

Comparing given equation with the standard equation, we get

a=-2

$\text{Hence, -2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

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