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LenaWriter [7]
3 years ago
15

Given the geometric sequence where a_1 = 3 and r = √2 find a_9

Mathematics
1 answer:
sesenic [268]3 years ago
4 0
To find n-therm of a geometric sequence, we are going to use the formula a_{n} =a _{1} r^{n-1}
where:
a_{n} is the term we are looking for
a _{1} is the first term 
r is the ratio 
n is the position of the number in the sequence 

From the question we now that a _{1} =3, r= \sqrt{2}, and n=9. Lets replace those values into our formula to get:
a _{9} =3( \sqrt{2} )^{9-1}
a_{9} =3 \sqrt{2} ^{8}
a_{9} =48

We can conclude that in our geometric sequence a_{9} =48; therefore, the answer is A.
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The solution to the given system of equation is (3, 3, 3)

<h3>Solving system of equations</h3>

Given the following system of equation expressed as:

2x-y+5z=16

X-6у +2z=-9

3x+4y- z=32

Multiply equation 2 by 2 to have:

2x-y+5z=16

2X-12у +4z=-18

Subtract

10y+z = 34 .........4

Similarly

3X-18у +6z=-27

3x+4y- z=32

Subtract

-22y+7z = -59 ........... 5

Equate 4 and 5

10y+z = 34 .........4 * 7

-22y+7z = -59 ........... 5 * 1

_______________________

70y+7z = 238

-22y+7z = -59

Subtract

92y = 297

y = 3

Recall that

10y+z = 34

10(3) + z = 34

z = 3

Since x - 6y +2z = -9

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Hence the solution to the given system of equation is (3, 3, 3)

Learn more on system of equation here: brainly.com/question/25976025

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