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LenaWriter [7]
3 years ago
15

Given the geometric sequence where a_1 = 3 and r = √2 find a_9

Mathematics
1 answer:
sesenic [268]3 years ago
4 0
To find n-therm of a geometric sequence, we are going to use the formula a_{n} =a _{1} r^{n-1}
where:
a_{n} is the term we are looking for
a _{1} is the first term 
r is the ratio 
n is the position of the number in the sequence 

From the question we now that a _{1} =3, r= \sqrt{2}, and n=9. Lets replace those values into our formula to get:
a _{9} =3( \sqrt{2} )^{9-1}
a_{9} =3 \sqrt{2} ^{8}
a_{9} =48

We can conclude that in our geometric sequence a_{9} =48; therefore, the answer is A.
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Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is a viable
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A linear equation is an equation where the highest degree in the equation is 1.

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for estimating the relation between the number of days the book is late and the total fine fee

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The equivalent equation to find the ordered pair will be y=0.3x

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4 0
2 years ago
85% of k is 68. What is k?
storchak [24]
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4 0
3 years ago
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Suppose a force of 30 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obe
AlexFokin [52]

Answer:

a) k = 300\,\frac{N}{m}, b) \Delta U_{k} = 13.5\,J, c) \Delta U_{k} = 6\,J, d) \Delta U_{k} = 4.5\,J

Step-by-step explanation:

a) The spring constant is calculated by using this expression:

k = \frac{F}{x}

k = \frac{30\,N}{0.1\,m}

k = 300\,\frac{N}{m}

b) The work needed to compress the spring from its initial position is:

\Delta U_{k} = \frac{1}{2}\cdot k \cdot (x_{f}^{2}-x_{o}^{2})

\Delta U_{k} = \frac{1}{2}\cdot (300\,\frac{N}{m} )\cdot [(-0.3\,m)^{2}-(0\,m)^{2}]

\Delta U_{k} = 13.5\,J

c) The work needed to stretch the spring is:

\Delta U_{k} = \frac{1}{2}\cdot (300\,\frac{N}{m} )\cdot [(0.2\,m)^{2}-(0\,m)^{2}]

\Delta U_{k} = 6\,J

d) The work need to stretch the spring is:

\Delta U_{k} = \frac{1}{2}\cdot (300\,\frac{N}{m} )\cdot [(0.2\,m)^{2}-(0.1\,m)^{2}]

\Delta U_{k} = 4.5\,J

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