Answer:
b
Step-by-step explanation:
Y= 3x + 3. Use rise (how many it goes up or down) and divide it by run (how many it goes left or right) that number is your slope (aka M/ the number that goes with x. The number without the x attached is just where the line crosses the y axis
The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
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Answer:
no
Step-by-step explanation:
-7+x^2-3x = 9+x-10
-7+(-2)^2-3*(-2) 9+(-2)-10
-7+4+6 9-12
3 > -3
if we substitute -2 to x, answer is not equal
The approximate area of the park on the grid is: E. about 40 km² to 50 km².
<h3>How to Find the Approximate Area on a Coordinate Grid?</h3>
The number of square on a coordinate grid that is covered determines the area covered. We can make an estimate by counting how many of this square on the coordinate grid that is covered, then find out the area depending on how much square area each grid represents.
In the coordinate plane given, which shows a park, we are told that each of the square on the grid equals 1 k = square kilometer.
The number of each of these squares we can find that is covered by the park on the grid is: 48 squares.
Therefore, the area of 48 squares on the grid = 48 × 1 = 48 km². Since not all squares are fully covered by the park, we can state that the approximate area of the park on the grid is: E. about 40 km² to 50 km².
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