Question

Part 6

Answer 1

Answer:

Part 1) The volume of each beam is $1,858.88\ ft^{3}$

Part 2) You can fill $26\ beams$

Part 3) Yes, the amount of sand left over is $1,669.12\ ft^{3}$

Step-by-step explanation:

Part 1) What is the total volume of each beam?

The volume of a cylinder is equal to

$V=\pi r^{2} h$

we have

$h=37\ ft$

$r=8/2=4\ ft$ ----> the radius is half the diameter

assume

$\pi=3.14$

substitute the values

$V=(3.14)(4)^{2} (37)$

$V=1,858.88\ ft^{3}$

Part 2) How many beams can you fill with this sand?

we know that

You are given a container with a 50,000 sq ft of sand for your beams

Note Is a 50,000 cubic foot  of sand instead of 50,000 sq ft of sand

Divide the total volume of sand by the volume of each beam to obtain the number of beams

$50,000/1,858.88=26.9\ beams$

Round down

$26.9=26\ beams$

Part 3) Will you have any sand left over? If so how much?

yes

$50,000-26(1,858.88)=1,669.12\ ft^{3}$