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3 years ago

I really need help with this guys please help it’s due tomorrow and I’m so frikin dumb

Mathematics

1 answer:

il63 [147K]3 years ago

5 0

Possible 24 impossible 3

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Find the sum of the first 9 terms in the following geometric series.

Nat2105 [25]

Answer:

The sum of the first 9 terms is $S_9=\frac{511}{4}$ .

Step-by-step explanation:

To find the sum of the first $S_n$ terms of a geometric sequence use the formula

$S_n=\frac{a_1(1-r^n)}{1-r}$

where, $n$ is the number of terms, $a_1$ is the first term and $r$ is the common ratio.

To find the common ratio, find the ratio between a term and the term preceding it.

Given the geometric sequence $64+32+16+...$ , the common ratio is

$r=\frac{32}{64} =\frac{1}{2}$

and the sum of the first 9 terms is

$S_9=\frac{64(1-(\frac{1}{2})^9)}{1-\frac{1}{2}}\\\\S_9=\frac{64\left(-\left(\frac{1}{2}\right)^9+1\right)}{\frac{1}{2}}\\\\S_9=\frac{64\left(-\frac{1}{2^9}+1\right)}{\frac{1}{2}}\\\\S_9=\frac{64\left(-\frac{1}{512}+1\right)}{\frac{1}{2}}\\\\S_9=\frac{64\left(1-\frac{1}{512}\right)\cdot \:2}{1}=\frac{128\left(-\frac{1}{512}+1\right)}{1}\\\\S_9=\frac{128\cdot \frac{511}{512}}{1}=\frac{511\cdot \:128}{512}=\frac{65408}{512}=\frac{511}{4}$

7 0

3 years ago

Read 2 more answers

Please help me on this (picture)

MissTica

There isn't a picture to help you with.

8 0

3 years ago

How far away is the moon

otez555 [7]

Answer : 238,900 mi

3 0

3 years ago

X(3, 4); scale factor = 7

Minchanka [31]

Answer:

(21, 28)

Step-by-step explanation:

Multiply coordinates by 7.

8 0

3 years ago

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On Monday, students at a summer camp spent 4 hours 25 minutes at the pool learning to swim. In the morning, they spent 2 hours 4

Lilit [14]

4 hours and 25 minutes simplifies to 265 minutes
2 hours and 48 minutes simplifies to 168 minutes

Subtract the numbers: 265-168 = 97 minutes left

Convert back to hours and you have 1 Hour 37 minutes at the pool in the afternoon.

5 0

3 years ago