Answer:
Step-by-step explanation:
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
9/5 is the answer, hope this helps
Diagonals bisect each other



Option B
Answer:
The exact volume of a cone is 10 yd³.
Step-by-step explanation:
Given:
Height of cone (h) is 6 yd and base (b) is 5 yd.
Now, to get the volume we need to find the radius.
So, to find radius we put the formula of base:
Let the radius be
Base=


Dividing both sides by π and using square root on both the sides:




Now, putting the formula for getting the volume (v) of cone:
Volume = 


Substituting the value of
from equation (1), we get:

yd³
Volume of cone is 10 yd³
Therefore, the exact volume of a cone is 10 yd³.