You use the formula below...,
Angle theta = cos^-1 [scalar product of the two vectors ÷ multiplication of their moduli]
For example...the angle between
(2i + 3j) and (4i + 5j)
Angle theta = cos^-1 [( 2(4) + 3(5))÷((square root of (2^2 + 3^2))×(square root of (4^2 + 5^2))
Angle theta = cos^-1 [ 23 ÷ ((square root of(13)) × (square root of (41)]
Angle theta = 5°
Answer:
∠ B = 85°
Step-by-step explanation:
the inscribed angle B is half the measure of its intercepted arc AC , then
∠ B =
× 170° = 85°
Answer:
17
Step-by-step explanation:
8+9 is 17
Answer:
Infinite
Step-by-step explanation:
I hope this helps, if it doesn't then just message me and ill be more than happy to help :)