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2 years ago

How many complex roots does the polynomial equation below have?

Mathematics

1 answer:

erastova [34]2 years ago

5 0

Answer:

Step-by-step explanation:

I will have one real root = fifth root of 3.

As it has a total of 5 roots ( By the Fundamental Theorem of Algebra) then it must have 4 complex roots.

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-9 + 3x = 9 Please Answer Correctly

muminat

Answer:

x=6

Step-by-step explanation:

Hope this helps if you so please mark me Brainliest I would greatly appreciate it. Peace and Love

7 0

3 years ago

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Write each expression in simplified radical form PLEASE HELP ITS DUE FRIDAY AND I DONT UNDERSTAND THIS AT ALL REALLY BAD TEACHER

Nonamiya [84]

Answer:

1) The simplified radical form is $\sqrt{36x^2}=6x$

2) The simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) The simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) The simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

Step-by-step explanation:

1) Given expression is $\sqrt{36x^2}$

To find the simplified radical form of the given expression :

$\sqrt{36x^2}$

$=\sqrt{36\times x^2}$

$=\sqrt{36}\times \sqrt{x^2}$

$=\sqrt{6\times 6}\times \sqrt{x\times x}$

$=6\times x$

$\sqrt{36x^2}=6x$

Therefore the simplified radical form is $\sqrt{36x^2}=6x$

2)Given expression is $\sqrt{72x^3}$

To find the simplified radical form of the given expression :

$\sqrt{72x^3}$

$=\sqrt{72\times x^3}$

$=\sqrt{72}\times \sqrt{x^3}$

$=\sqrt{9\times 8}\times \sqrt{x\times x\times x}$

$=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}$

$=3\times 2\sqrt{2}\times x\sqrt{x}$

$\sqrt{72x^3}=6x\sqrt{2x}$

Therefore the simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) Given expression is $\sqrt{15x^8}$

To find the simplified radical form of the given expression :

$\sqrt{15x^8}$

$=\sqrt{15\times x^8}$

$=\sqrt{15}\times \sqrt{x^8}$

$=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}$

$=\sqrt{15}\times x^4$

$\sqrt{15x^8}=\sqrt{15}x^4$

Therefore the simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) Given expression is $\sqrt{36x^7}$

To find the simplified radical form of the given expression :

$\sqrt{36x^7}$

$=\sqrt{36\times x^7}$

$=\sqrt{36}\times \sqrt{x^7}$

$=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}$

$=6\times x^3\sqrt{x}$

$\sqrt{36x^7}=6x^3\sqrt{x}$

Therefore the simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

3 0

3 years ago

Your mother has a new cell phone. It comes with 18 applications already installed. She uses only "2" /"3" of those applications.

Slav-nsk [51]

Answer:

its 2/3(18) + 12 = 24

Step-by-step explanation:

3 0

2 years ago

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What is the value of sin2a + cos2a + sec2a-tan2a <br> Please

Artemon [7]

Answer:

Step-by-step explanation:

sin²a + cos²a + sec²a - tan²a

sin²a + cos²a = 1

1 + tan²a = sec²a

So, sec²a - tan²a = 1

sin²a + cos²a + sec²a - tan²a

= 1 + 1 = 2

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3 years ago

Why does a nail stick to a magnet?

sergij07 [2.7K]

The nail will stick to the magnet because it will become magnetized.Also because the north pole in the magnet rearranges the magnet domains inside the steel so that their south poles all point toward the north pole of the permanent magnet

7 0

3 years ago

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