The paper is 16 cm by 34 cm to start with, so we started with area
.. (16 cm)*(34 cm) = 544 cm^2
A circle of diameter 16 cm has been removed. The area of that circle is
.. π*(d/2)^2 = 3.14*(16 cm/2)^2 = 200.96 cm^2
Then the area of the paper that remains is
.. 544 cm^2 -200.96 cm^2
.. = 343.04 cm^2
(B) Opposite sides are equal (otherwise, trapezoid, etc)
3÷8+1÷8-(9÷8+5÷8)
=3÷8+1÷8-(14÷8)
=3÷8+1÷8-14÷8
=(3+1-14)÷8
=-10÷8
=-5÷4
=-1.25
Equilateral triangle have the same side lengths. Perimeter = sum of all sides
(4x - 3) + (4x - 3) + (4x - 3) = 63
Remove parentheses
4x - 3 + 4x - 3 + 4x - 3 = 63
Combine like terms
12x - 9 = 63
12x = 72, x = 6
Solution: x = 6