Answer:
sadfasdfasdfasdf
Step-by-step explanation:
asdfasdfasdfsadfsadfsadfsdfsdfsaf
The answer to your question is 503
Answer:
p=7
Step-by-step explanation:
pqrs equal to tuv perimeters =60
triangle=20×3
60
Trapezium=(p+8)+12+12+3p
60=4p+32
4p=28
p=7
Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore,
k^2+12k-8k=0
Thus,
The equations he must solved now is k^2-8+12=0