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9966 [12]
4 years ago
10

What is the inequility?

Mathematics
1 answer:
bija089 [108]4 years ago
4 0
E> 8 think is the answer
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An experienced landscaper thought it would be funny to play a joke on some rookie landscapers. The rookies were given the measur
pashok25 [27]

Answer:

48∛9 ft²

Step-by-step explanation:

The length (L) and width (W) are given by:

L = 4\sqrt[3]{24}\\ W= 6\sqrt[3]{3}

Since this is a rectangular region, the area is given by:

A=L*W=L \\A=4\sqrt[3]{24}* 6\sqrt[3]{3}\\A=24\sqrt[3]{72}\ ft^2

The answer can be further simplified by factoring as follows:

A=24\sqrt[3]{72} = \\A=24\sqrt[3]{2*2*2*3*3}= 24\sqrt[3]{2^3*9}\\A=48\sqrt[3]{9}\ ft^2

The exact area is its simplest form is 48∛9 ft²

6 0
3 years ago
(x+3)*(x+4)*(x+5)*(x+6)+1
Drupady [299]
There is it hope u have a good day

ANSWER:

6 0
3 years ago
An earthquake with a magnitude of about 2. 0 or less is called a microearthquake. It is not usually felt. The intensity of an ea
Alecsey [184]

The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .

<h3>What is magnitude of earthquake?</h3>

Magnitude of earthquake is the measure of the size of origin of the earthquake. The magnitude of the earthquake keeps the same value for each place.

An earthquake with a magnitude of about 2. 0 or less is called a micro-earthquake and not felt usually.The intensity of an earthquake with a magnitude of 2.

Let the intensity of this earthquake is <em>n </em>times greater than the intensity of an a standard earthquake. Thus the intensity of standard earthquake can be given as,

n=10^2\\n=100

If the magnitude would be 3 then the intensity would be,

n=10^3\\n=1000

It would be 1000 times greater than the standard earthquake and so on.

Thus, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .

Learn more about the magnitude of earthquake here;

brainly.com/question/18109453

8 0
3 years ago
Solve for x -6x + 7 &gt; 1
Elenna [48]

the answer is 6/5

-5x>-6

x>-6/-5

x>6/5

5 0
4 years ago
Read 2 more answers
How can I solve this question???
eduard

Answer:

144°

Step-by-step explanation:

step 1

Find the measure of the central angle of the regular pentagon

Divide 360 degrees by 5 (the number of sides)

360\°/5=72\°

Let

c----> the center of the pentagon

we know that

m∠ECA=72°

m∠ACB=72°

therefore

m∠ECB=m∠ECA+m∠ACB

substitute the values

m∠ECB=72°+72°=144°

The measure of angle ECB is equal to the degrees that the pentagon rotate

5 0
3 years ago
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