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myrzilka [38]
3 years ago
10

Yoon has a number of dimes and quarters she wants to put into rolls. She has 124 coins in all that add up to $20.50. If a roll o

f quarters is equal to ten dollars, how many extra quarters does she have that will not fill up a roll?
Mathematics
1 answer:
Xelga [282]3 years ago
5 0
A) D + Q = 124
B) .10D + .25Q = 20.50

Multiply B) by -4
B) -.40D + -Q = -82.00 then add to A)
A) D + Q = 124

.60 D = 42
D = 70 Dimes
Q = 54 Quarters

A roll of quarters = $10 = 40 Quarters so there will be 14 "extra" quarters.


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√m/3=4<br> My teacher didn't explain how to solve these to well can someone explain?
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√m/3 = 4

To remove the radical sign, square both sides.

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3 0
3 years ago
A person in a casino decides to play 3 games of blackjack. let w denote a win and l denote a loss. define the event a as "the pe
Ann [662]

Answer: The answer is {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.



Step-by-step explanation: Given that a person in the casino is going to play 3 games of blackjack. Here, 'w' denotes a win and 'l' denotes a loss.  

Also, let 'A' be the event that the person wins at least one game of blackjack. Then, the outcomes of Event 'A' are

(i) win in 1st game     loss in 2nd game       loss in 3rd game

(ii) win in 1st game     win in 2nd game        loss in 3rd game

(iii) win in 1st game     loss in 2nd game       win in 3rd game

(iv) win in 1st game     win in 2nd game        win in 3rd game

(v) loss in 1st game     loss in 2nd game       win in 3rd game

(vi) loss in 1st game     win in 2nd game        loss in 3rd game

(vii) loss in 1st game     win in 2nd game       win in 3rd game

Thus, the outcomes of the event A are (w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l) and (l, w, w).

Thus, A = {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.


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3 years ago
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