Tehara has read 115 pages of a 305 page book she reads 10 pages each day how many days will it take to finish
2 answers:
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Answer:
The concentration of the drug is 50mg/mL.
Step-by-step explanation:
This problem can be solved by a rule of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
In this problem, as the number of mg increases, so does the number of mL. It means the we have a direct rule of three.
Tha problem states that the antibody is available in a prefilled syringe containing 40 mg/0.8 mL. Calculate the concentration of drug on a mg/mL basis.
The problem wants to know how many mg are there in a mL of the drug.
40mg - 0.8mL
x mg - 1 mL
0.8x = 40
x = 50mg.
The concentration of the drug is 50mg/mL.
Answer:
<h2>The graph is in the attachment</h2>Step-by-step explanation:
<, > - dotted line
≤, ≥ - solid line
<, ≤ - shaded region below a line or to the left if is a vertical line
>, ≥ - shaded region above a line or to the right if is a vertical line
----------------------------------------------------------
We have x ≥ 4:
solid vertical line x = 4
shaded region to the right
0.75 liter of 0.07 % is used and 0.25 liter of 0.23 % salt is used
<em><u>Solution:</u></em>
We have to 1 liter of final solution
Let "x" be the salt solution of 0.07 %
Then, (1 - x) is the salt solution of 0.23 %
Then final solution should be 1 liter of solution which contains 0.11 % salt
Thus, 0.07 % of "x" is mixed with 0.23 % of (1 - x) to make a solution 0.11 % of 1 liter
<em><u>Thus a equation is framed as:</u></em>
0.07 % of x + 0.23 % of (1 - x) = 0.11 % of 1
Thus 0.75 liter of 0.07 % is used
And,
1 - x = 1 - 0.75 = 0.25
Thus 0.25 liter of 0.23 % salt is used