Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)
we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5
slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1
slope=-1
Answer:
-10
Step-by-step explanation:
Solving for y gives ...
20y = 2x +6
y = 2/20x +6/20 = 1/10x +3/10
The slope of the given line is the coefficient of x: 1/10. The slope of the perpendicular line is the opposite reciprocal of this: -1/(1/10) = -10.
The perpendicular line has a slope of -10.
Answer:
The answer is 15
Step-by-step explanation:
I know and is not stupid
The only consistent right answer will be B.
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