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harkovskaia [24]
2 years ago
15

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log2, então o valor de é

Mathematics
1 answer:
sveticcg [70]2 years ago
4 0

Answer:

\frac{x}{y}=1.3

Step-by-step explanation:

<u>Informação recuperada:</u>

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é

1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:

10x=20y \Rightarrow x=log_{10}20y

2) Aplicando a propriedade do produto de logaritmo:

log(AB)= logA+logB

x=log_{10}20y \Rightarrow x=log(2+10)y\Rightarrow x=(0.3+1)y \Rightarrow x=1.3y

3)  Como quero o quociente divido ambos os lados por y

\frac{x}{y}=\frac{1.3y}{y}\Rightarrow \frac{x}{y}=1.3

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