Pi r² is circle's area expression.
So the r is radius,.
Given that <span>v=234 3√p/w (cube root)
where </span><span>
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour
p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity
v = 234 </span><span>3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.</span>
Answer: 15
Step-by-step explanation:
For this you will have to use pythagoras’ theorem.
The formula for the shorter side of this triangle is u²=c²-b² (or in this case u²=17²-8²).
17²=289
8²=64
The formula becomes u²=289-64 or u²=225
Then to find u on its own you have to square root 225.
The square root of 225 is 15.
Answer:
1/3
Step-by-step explanation:
(5 + 4 + 3 + 3) x 2 = 30
Multiplied by two because two marbles are being picked.
10/30 = 1/3
Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2
