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3 years ago

1/3÷7 3/4 dividing fraction

Mathematics

1 answer:

Ede4ka [16]3 years ago

6 0

Answer:

4/93 or 0.04301075...

Step-by-step explanation:

Reduce the expression by cancelling the common factors

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1,275/5 find the unit rate

Pachacha [2.7K]

Answer:

255

Step-by-step explanation:

1,275/5 = 255

3 0

2 years ago

A grocer wanted to mix 19 liters milk of $2.2 with 1 kg cacao to make a mixture of hot chocolate. What should be the cost of mil

Ad libitum [116K]

Answer:

for this, I'm going to assume that the cacao powder costed $2.2. If the cacao costs $2.2 then the milk will cost $0.8.

Step-by-step explanation:

If you subtract 2.2 from 3 then you get 0.8. Also if you add 2.2 with 0.8 then you get 3. another way to simplify it is to add one zero on the end, like this 22+8=30.

4 0

3 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

14 is the GCF of anumber M and 210. What are possible values of M?

Cloud [144]

14 = GCF of M and 210
M = possible values

GCF = Greatest common denominator
Now, let’s start decomposing
=> 210 | 2
=> 105 | 2
=> 35 | 5
=> 7 | 7
=> 1

Thus, 2 x 3 x 5 x 7 = 210

Now let’s find the factors of 14
=> 14 | 2
=> 7 | 7
=> 1

Thus, 2 x 7 = 14

Notice that’s there’s no 14 in 210 shown factors, but the only GCF found is 7.
Thus, the value of M that we’re looking for is infinite. All numbers that has the GCF of 7 are applicable.

6 0

3 years ago

What is the value of w?

Dima020 [189]

You do 65+90=155
then 180-155=25 to get the angle next to w
w=155

7 0

3 years ago