There are 52 weeks in a year. 1 frog per week: 52 * 1 = 52
So, cloning about 1 frog per week would be reasonable.
Answer:
a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]
Step-by-step explanation:
a.We know that
e^jθ = cosθ + jsinθ and
e^(-jθ) = cosθ - jsinθ
Adding both equations, we have
e^jθ = cosθ + jsinθ
+
e^(-jθ) = cosθ - jsinθ
e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ
Simplifying, we have
e^jθ + e^(-jθ) = 2cosθ
dividing through by 2 we have
cosθ = ¹/₂[e^jθ + e^(-jθ)]
b. We know that
e^jθ = cosθ + jsinθ and
e^(-jθ) = cosθ - jsinθ
Subtracting both equations, we have
e^jθ = cosθ + jsinθ
-
e^(-jθ) = cosθ - jsinθ
e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)
Simplifying, we have
e^jθ - e^(-jθ) = 2jsinθ
dividing through by 2 we have
sinθ = ¹/₂[e^jθ - e^(-jθ)]
AB = √(5-0)^2 + (4-0)^2 = √25+16 = √41
BC = √(0-5)^2 + (8-4)^2 = √25+16 = √41
CD = √(-5 - 0)^2 + (4-8)^2 = √25+16 = √41
AD = √(-5-0)^2 + (4-0)^2 = √25+16 = √41
All the sides are equal so it is either a square or a rhombus.
The distance from A to C on the x axis is: 8-0 = 8 units.
The distance from B to D on the Y axis is: 5 - - 5 = 10 units.
Because the two distances are not the same, it is not a square.
The answer is 4. AB=BC ; therefore, ABCD is a rhombus.
The volume of a cube is side length cubed (s^3)
So if you know the volume then take the cube root of 1/512... which is 1/8
So each side of the cube is 1/8.
There are 6 congruent sides on a cube (picture a “dice”). Do the area of each side would be (1/8)(1/8)= 1/64 then multiply that area by 6 and reduce ... you get 6/64 = 3/32 for the surface area
The Aon Center is taller. You just need to look at the place values, like 5 and 10. Which is bigger? the ten of course.
