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Andreyy89
2 years ago
5

A grocer wanted to mix 19 liters milk of $2.2 with 1 kg cacao to make a mixture of hot chocolate. What should be the cost of mil

k, if the total mixture costed 3 dollars?
Mathematics
1 answer:
Ad libitum [116K]2 years ago
4 0

Answer:

for this, I'm going to assume that the cacao powder costed $2.2. If the cacao costs $2.2 then the milk will cost $0.8.

Step-by-step explanation:

If you subtract 2.2 from 3 then you get 0.8. Also if you add 2.2 with 0.8 then you get 3. another way to simplify it is to add one zero on the end, like this 22+8=30.

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Okay so you would line them up then you would multiple 5 and 0 then 7 and 5 and then you add a 0 then you would get the answer 350 then you would multiply the same numbers then the answer you would get is 3500 then you add 3500+350=3850

6 0
2 years ago
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According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio
joja [24]

Answer:

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

p_v =P(t_{44}>2.73)=0.0045    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation    

\bar X=86.7 represent the average life for the sample    

s=8.6 represent the population standard deviation    

n=45 sample size    

\mu_o =83.2 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \leq 83.2  

Alternative hypothesis :\mu > 83.2  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

Give the appropriate conclusion for the test  

First we need to calculate the degrees of freedom given by:

df=n-1=45-1=44

Since is a one side right tailed test the p value would be:    

p_v =P(t_{44}>2.73)=0.0045    

Conclusion    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

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2 years ago
Formulating and solving inverse variation functions
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Answer:

See below.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Please help me and if you need help with any questions i will return thank ya
Charra [1.4K]
Step two is the answer i hope that helps
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3 years ago
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