All categories

2 years ago

Easy math please help i'll mark brainliest

Mathematics

2 answers:

gregori [183]2 years ago

8 0

47 I hope this helps you

katen-ka-za [31]2 years ago

5 0

Answer:

D, D, A, C

Step-by-step explanation:

Congruent means equal.

T and r are alternate angles

Vertically opposite angles are equal

Y is 47 degrees because since the full angle is 90 degrees, subtract:

90-43 = 47

Hope this helps :)

-jp524

You might be interested in

What is the answer to 2/3 of 5

liraira [26]

Answer:

3.333333333333...

Step-by-step explanation:

6 0

2 years ago

a shop has a sale and reduces all the prices by 15k in naira.find the sale price of an article of an article marked at 750naira

Andrej [43]

Answer:

Question (i):

Reduce = 15% of Rs 40 = 0.15 x 40 = Rs 6

Price after reduced = Rs 40 - Rs 6 = Rs 36

Answer: Rs 36

Question (ii):

Reduce = 15% x 20.40 = 0.15 x 20.40 = Rs 3.60

Price after reduced = Rs 20.40 - Rs 3.60 = Rs 17.34

Answer: Rs 17.34

3 0

3 years ago

Evaluate:

Anni [7]

Answer:

a) = 4.5

b) = 3.3

Step-by-step explanation:

Before solving our problems given to us let us under stand the rule of cube roots

It says $\sqrt[3]{x \times x \times x} = x$ -----(A)

Also

$\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y$ ---(B)

Now let us see each part one by one

a) we have

$\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}$

Now 64 = 4 x 4 x 4

0.027 = 0.3 x 0.3 x 0.3

0.008 = 0.2 x 0.2 x 0.2

substituting these values

$\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}$

Applying Rule A in above

$=4+0.3+0.2$

$=4+0.5$

4.5

b) we have $\sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}$

Applying the B rule in this

$=0.3 \times 11$

3.3

4 0

3 years ago

Sofia has four times as many dollars as her friend jessie has. together the two have $35. how much money do they each have?

garik1379 [7]

4J = s
J + s = J + 4j = 5j = 35

J = 7
s = 28

3 0

2 years ago

A ramp into a building forms a 6° angle with the ground. If the ramp is 8 feet long, how far away from the building is the entry

Sauron [17]

Answer:

7.96 ft

Step-by-step explanation:

Given;

Length of ramp L = 8 ft

Angle with the horizontal (ground) = 6°

Applying trigonometry;

With the length of ramp as the hypothenuse,

The horizontal distance d as the adjacent to angle 6°

Since we want to calculate the adjacent and we have the hypothenuse and the angle. We can apply cosine;

Cosθ = adjacent/hypothenuse

Substituting the values;

Cos6° = d/8

d = 8cos6°

d = 7.956175162946

d = 7.96 ft

The building is 7.96ft away from the entry point of the ramp.

6 0

3 years ago