What are the minimum, first quartile, median, third quartile, and maximum of the data set? 45,76,12,39,87,65,23,32

1 answer:

6 0

Minimum=12, Q1=27.5,median=42,Q3=70.5,maximun=87. To get your answer you need to use a graphing, go to stat, edit, add all the number in L1, you press stat again, you go to CALC and press number 1 and enter.it seem a lot but it's pretty fast. hope this helps.if if does please add brainliest

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Correct answers only please!

Naily [24]

Answer:

1st Question

A. 85

2nd Question

B. 71

Step-by-step explanation:

1st Question

{90 + 94 + 96 + 90} = 370/4 = 92.5

{95 + 99} = 194/2 = 97

{87 + 75 + 82 + 85} = 329/4 = 82.25

{71} = 71/1 = 71

.20(92.5) +.25(97) +.30(82.25) +.25(71) = 85.175 Rounded-up = 85

___________________________________________________

2nd Question

.10(95) +.20(80) +.50(67) +.20(60) = 71

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3 years ago

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Sergeeva-Olga [200]

Answer:

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3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind

liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± $t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )$