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klio [65]
3 years ago
8

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 45,76,12,39,87,65,23,32

Mathematics
1 answer:
Tatiana [17]3 years ago
6 0

Minimum=12, Q1=27.5,median=42,Q3=70.5,maximun=87. To get your answer you need to use a graphing, go to stat, edit, add all the number in L1, you press stat again, you go to CALC and press number 1 and enter.it seem a lot but it's pretty fast. hope this helps.if if does please add brainliest

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Use factoring by difference of squares to solve the equation, x^2 - 81 = 0.
Bas_tet [7]
The answer is B +/- 9 !!
7 0
3 years ago
Weight gain during pregnancy. In 2004, the state of North Carolina released to the public a large data set containing informatio
pychu [463]

Answer:

1. B. H0: μ1−μ2=0, HA: μ1−μ2≠0

2. z=1.2114

3. P-value=0.2257

4. Do not reject H0

Step-by-step explanation:

We have to perfomr an hypothesis test to see if there is strong evidence that there is a significant difference between the two population means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2\neq0

Being μ1 the mean average gain for younger mothers and μ2 the mean average gain for mature mothers.

(NOTE: we are comparing means, not proportions, as it is the random variable is the weight gain).

As we are claiming "strong evidence", the level of significance will be 0.01.

For younger mothers, the sample size is n1=840, the sample mean is 30.7 and  the sample standard deviation is s1=14.91.

For mature mothers, the sample size is n2=132, the sample mean is 29.15 and the sample standard deviation is s2=13.46.

The difference between means is

M_d=\mu_1-\mu_2=30.7-29.15=1.55

The standard error of the difference between means is

s_M=\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}=\sqrt{\dfrac{14.91^2}{840}+\dfrac{13.46^2}{132}}=\sqrt{ 0.2647+1.3725}=\sqrt{1.6372}\\\\\\s_M=1.2795

Then, the statistic can be calculated as:

z=\dfrac{M_d-(\mu_1-\mu_2)}{s_M}=\dfrac{1.55-0}{1.2795}=1.2114

The P-value for this z-statistic in a two tailed test is:

P-value=2P(z>1.2114)=0.2257

As the P-value is greater than the significance level, the null hypothesis failed to be rejected.

There is no enough evidence to claim that the real average weight gain differs from mature and youger mothers.

5 0
4 years ago
Math help please thanks
Y_Kistochka [10]
Please don't post a set of problems with no work of your own shown.
I would gladly involve you in answering these questions, but will not do the problems and hand you direct answers.  Start with #1.  What do you understand about this problem, and what do you think you need to know to be able to solve it?
4 0
3 years ago
The numerator of a fraction is 6 more than the denominator. If 5 is subtracted from the denominator, the fraction becomes 3/2. F
sattari [20]

Answer:

The fraction is 32/27

Step-by-step explanation:

let the fraction be x/y

x - y = 6

x = 6 + y ••••••(i)

This is according to the first sentence

Furthermore;

x/y-5 = 3/2

2x = 3(y-5) •••••(ii)

Substitute

2(6 + y) = 3y - 15

12 + 2y = 3y - 15

3y -2y = 12 + 15

y = 27

x = 6 + y

x = 6 + 27 = 33

6 0
3 years ago
1. Erin hits a golf ball off a tee. The height, yin yards, of the ball off the ground is given by
Sladkaya [172]

Answer:

The maximum height of the ball is 28.2 yards.

Step-by-step explanation:

When we have a quadratic equation in the following format:

y = ax^{2} + bx + c

The maximum value happens when

x = x_{v} = \frac{-b}{2a}

The maximum value will be y(x_{v})

In this problem, we have that:

y = -0.0018x^{2} + 0.45x + 0.05

So

a = -0.0018, b = 0.45, c = 0.05

x = x_{v} = \frac{-b}{2a} = \frac{-0.45}{2*(-0.0018)} = 125

The maximum height is:

y(125) = -0.0018*(125)^{2} + 0.45*125 + 0.05 = 28.2

The maximum height of the ball is 28.2 yards.

4 0
3 years ago
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