> -1 2/3 ÷ (-2 1/5)
> -1.66.. ÷ -2.2
> 0.75454...
Answer: 0.75
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to

.

---> equation (1)
By using pythagoras rule which states that the

---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,

substitute this value in equation (1) then

where A is the area of the square whose side is x
Answer:
she end
Step-by-step explanation:
bansnd
Answer:
B
Step-by-step explanation:
IQR is the higher qurtile subtracted by the lower qurtile so higher is 40 and lower is 20 so 14
Hope this helps have a great day:)