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4 years ago

Name two ways that carbon enters the atmosphere

Biology

2 answers:

iragen [17]4 years ago

5 0

Fossil fuels and natural gasses are two ways

antiseptic1488 [7]4 years ago

4 0

fossil fuels and respiration.

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A vegtable garden is 12 meters long by 7 meters wide. In one square meter, you count two toads. Estimate the population of toads

marysya [2.9K]

Answer:

168 toads

Explanation:

First we need to find the area of the garden. Area = length x width

Area = 12m x 7m = 84 m²

2 toads/ 1 sq m

84(2) = 168

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2 years ago

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sergij07 [2.7K]

2 and 3 are too similar to distinguish because they both are saying it's been back up on several different accounts but 3 seems like a more solid answer go with 3

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3 years ago

Which of the following<br> would we most likely find water in a form of a gas

SpyIntel [72]

Wouldn't it be water vapor? Don't quote me on this, but I think when water Molecules (H2O) heat up, they expand away from each other and become gas.

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3 years ago

An organism can have how many genus and species names

Fudgin [204]

i know the answer is false

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3 years ago

12.36Un balón lleno contiene 12 kg de oxígeno, O2, bajo una presión ma-nométrica de 40 atm. Determine la masa de oxígeno que se

const2013 [10]

Answer:

Quedan 7.317 kilogramos de oxígeno en el balón y se extraen 4.683 kilogramos de oxígeno en el proceso.

Explanation:

Asúmase que el balón es rígido. Supongamos que el oxígeno se comporta como un gas ideal, entonces la ecuación de estado es la siguiente:

$P\cdot V = \frac{m\cdot R_{u}\cdot T}{M}$ (1)

Donde:

$P$ - Presión, medida en atmósferas.

$V$ - Volumen, medido en litros.

$m$ - Masa, medida en kilogramos.

$M$ - Masa molar, medida en kilogramos por kilomol.

$T$ - Temperatura, medida en Kelvin.

$R_{u}$ - Constante de los gases ideales, medida en atmósfera-litros por kilomol-Kelvin.

El aire experimenta un proceso isocórico e isotérmico, entonces obtenemos la siguiente relación:

$\frac{P_{1}}{m_{1}} = \frac{P_{2}}{m_{2}}$ (2)

Nótese que los subíndices 1 y 2 representan los estados inicial y final de proceso.

Si sabemos que $P_{1} = 41\,atm$ , $m_{1} = 12\,kg$ y $P_{2} = 25\,atm$ , entonces la masa final del aire es:

$m_{2} = \frac{P_{2}}{P_{1}} \cdot m_{1}$

$m_{2} = \left(\frac{25\,atm}{41\,atm}\right)\cdot (12\,kg)$

$m_{2} = 7.317\,kg$

La masa que se ha extraído del balón es:

$\Delta m = m_{1}-m_{2}$

$\Delta m = 12\,kg-7.317\,kg$

$\Delta m = 4.683\,kg$

Quedan 7.317 kilogramos de oxígeno en el balón y se extraen 4.683 kilogramos de oxígeno en el proceso.

8 0

3 years ago