Given:
JK is tangent to a circle with center H
To find:
The length of HK.
Solution:
The image is attached below.
JK = 8 mi, HJ = 15 mi
JK is tangent to a circle.
The tangent is always perpendicular to the radius.
Therefore, m∠J = 90°
Using Pythagoras theorem:
HK² = JK² + HJ²
HK² = 8² + 15²
HK² = 64 + 225
HK² = 289
HK² = 17²
Taking square root on both sides.
HK = 17
The length of HK is 17 mi.
X = 96
100 137.4
137.4x=(100)(96)
137.4x=9600
137.4x/137.4=9600/137.4
x=70%
4 = - 3(2) + c
4 = - 6 + c
c = 10
y = - 3x + 10
Answer: x= 207.8873386
Step-by-step explanation:
expecting both 2x-15 and 3x are angles in radiant, let's draw a rhombus ABCD
∠ABC = 2x-15
∠ BCD = 3x
∠ABC + < BCD= π ( 180° in radiant)
2x - 15 + 3x = π
5x - 15 = π
x - 3 = 1/5π
= 3.628318531 = 207.8873386
2x−15°+3x=180
5x-15°=180
5x=195°
x=39°