Write an equation that represents the action in water of rubidium hydroxide as an Arrhenius base.
1 answer:
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Hello!
To solve this question, we need to use the Avogadro's Number, which is a constant first discovered by Amadeo Avogadro, an Italian scientist. He discovered that in a mole of a substance, there are 6,02*10²³ molecules. Using this relationship, we apply the following conversion factor:
So, 8,50 * 10²⁴ molecules of Na₂SO₃ represent 14,12 moles of Na₂SO₃
Have a nice day!
To solve this question, we need to use the Avogadro's Number, which is a constant first discovered by Amadeo Avogadro, an Italian scientist. He discovered that in a mole of a substance, there are 6,02*10²³ molecules. Using this relationship, we apply the following conversion factor:
So, 8,50 * 10²⁴ molecules of Na₂SO₃ represent 14,12 moles of Na₂SO₃
Have a nice day!
Answer:
1711.11L
Explanation:
Given parameters:
Mass of methane = 1kg = 1000
Temperature of gas = 35°C
Pressure of the gas = 0.9atm
Converting to the temperature to kelvin, we have:
35+ 273 = 308k
Solution
From the given parameters, we can solve this problem using the ideal gas equation which is combination of the gas laws. It is expressed below:
PV = nRT .......................(i)
Where P is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the temperature
Now, from the above parameters, we have two unknowns which are n and V.
To find the number of moles n, we use the expression below:
number of moles =
molar mass of methane = 12 + (4x1) = 16g/mol
Number of moels of methane = = 62.5mole
Now that we know the number of moles, we can make the unknown Volume the subject of the formula:
V =
V = = 1711.11L
Answer: 1. 3.23 m
2. 32.4
3. B adding solvent and C removing solute
Explanation:
1. Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent
where,
n = moles of solute
= weight of solvent
Now put all the given values in the formula of molality, we get
2. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
Therefore, the moles of is 32.4
3. Molarity can be decreased by decreasing the moles of solute and by increasing the volume of solution.
Thus adding solvent and removing solute will decrease the molarity.