A 62 gram sample of Fe-53 decays for 34.04 minutes. What mass of iron remains?

Chemistry

1 answer:

kakasveta [241]3 years ago

5 0

Mass of iron remains : 3.875 g

<h3>Further explanation</h3>

Given

62 gram sample of Fe-53 decays for 34.04 minutes.

Required

mass of iron remains

Solution

Hal life of Fe-53 = 8.51 min

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

No=62 g

t = 34.04 min

t1/2 = 8.51 min

Input the value :

$\tt Nt=62.\dfrac{1}{2}^{34.04/8.51}\\\\Nt=62.\dfrac{1}{2}^4\\\\Nt=3.875~g$

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