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3 years ago

A reaction occur when aqueous solutions of copper(II) chloride and barium hydroxide are combined.

Chemistry

1 answer:

Mamont248 [21]3 years ago

6 0

CuCl₂ copper (II) chloride

Ba(OH)₂ barium hydroxide

<u>net ionic equation</u>:

Cu²⁺ (aq) + 2 Cl⁻ (aq) + Ba²⁺ (aq) + 2 (OH)⁻ (aq) → Cu(OH)₂ (s) + 2 Cl⁻ (aq) + Ba²⁺ (aq)

where:

(aq) - aqueous state

(s) - solid

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) How many moles are there in 2.00 x 10^19 molecules of calcium phosphate?

Tamiku [17]

Answer:

$\huge 3.322 \times {10}^{ - 5} \: \: moles \\$

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{2.00 \times {10}^{19} }{6.02 \times {10}^{23} } \\ \\ = 3.322 \times {10}^{ - 5} \: \: moles$

Hope this helps you

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3 years ago

What is the chemical equation of ccl4, please explain thank you! :-D

Gekata [30.6K]

It could be
C + 2Cl2 ➡️ CCl4
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3 years ago

Given the unbalanced equation which represents aluminum metals reacting with an acid:

Alona [7]

There are three number of electrons lost by 1 mole of aluminium because aluminum has +3 charge on it.

<h3>What is cation?</h3>

When an atom loses electron, positive charge appears on the atom this is called cation. In this reaction we can see that aluminium has +3 charge which means that it loses 3 electrons.

So we can conclude that There are three number of electrons lost by 1 mole of aluminium because aluminum has +3 charge on it.

Learn more about electron here: brainly.com/question/23390564

#SPJ1

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2 years ago

Running for presindentr

irina1246 [14]

Answer:

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Explanation:

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3 years ago

Gaseous methane CH4 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.963

Anna71 [15]

Answer:

$m_{H_2O}=0.676gH_2O$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:

$0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O$

Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:

$m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O$

Regards!

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3 years ago