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3 years ago

Why people made up ratios ?

Mathematics

1 answer:

Allushta [10]3 years ago

8 0

They created ratios so people could get information.

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If f(x) = x/2 -3 and g(x) = 3x² + x - 6, find (f + g)(x). O A. 3x O B. 3x² + 3x-9 3x O C. 3.x2 + x - 3 O D. 4x2-9

Olenka [21]

Answer:

4x2-9

Step-by-step explanation:

it would be that because the number is in the c acis

8 0

3 years ago

What is negative times x plus 7

ValentinkaMS [17]

-.x+7
-x+7=0
-x=-7
x=7...

Not too sure because of the way you wrote the question but this is the interpretation i gave it.

3 0

3 years ago

Read 2 more answers

Create an equation to solve for x then solve for x.

Ratling [72]

Answer:

Step-by-step explanation:

In parallelogram adjacent angles are supplementary

∠U +∠V = 180

9x + 15 + 6x + 15 = 180

Combine like terms

9x + 6x + 15 + 15 = 180

15x + 30 = 180

Subtract 30 from both sides

15x = 180 - 30

15x = 150

Divide both sides by 15

x = 150/15

x = 10

∠U = 9x + 15

= 9*10 + 15

= 90 + 15

∠U = 105

∠V = 6x + 15

= 6*10 + 15

= 60 + 15

∠V = 75

5 0

3 years ago

Find the area of the triangle below??

Sladkaya [172]

Answer:

94.8

Step-by-step explanation:

94.8 is the answer for 1st q

8 0

3 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

2 years ago