Answer:
Ummm. 1 & 3 look good double check 2
Step-by-step explanation:
HELPFUL?
Answer:
The maximum power generated by the circuit is 300 watts.
Step-by-step explanation:
A quadratic function is one that can be written as an equation of the form:
f (x) = ax² + bx + c
where a, b and c (called terms) are any real numbers and a is nonzero.
In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.
The vertex is a point that is part of the parabola, which has the value as ordered minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.
The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:
- The value of x, in this case the value of current c in amperes, can be calculated with the formula
. In this case: 
So c= 5 amperes. The current is 5 amperes. - The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts
<u><em>The maximum power generated by the circuit is 300 watts.</em></u>
Answer:
20.00+12.76 would give you that sum
Step-by-step explanation:
First, subtract 24 - 14 to get how many books he had after he sold half of his collection and bought 14 more:
24 - 14 = 10
10 = number of books after he sold half of his collection.
Now, you need to multiply 10 x 2, because you need to find the original number of comic books:
10 x 2 = 20
He originally had 20 comic books.
An equation you could use for this question is:
2(24 - 14) = x. (X = number of comic books)
Hope this helps!!
~Kiwi
I am going to assign the first image to problem 2, the second image to problem 3, and the third image to problem 4 and solve for x in each image. Basically, all of these problems can be solved used the law of sines which is as follows:
a/sinA = b/sinB = c/sinC
This states that the length of a side, divided by the sine of the opposite angle, is the same for every side in a triangle.
2.) We must solve for side x in the smaller triangle. We know two sides of the large triangle, and one side of the smaller triangle. The two parallel lines tell us that angle A = angle N and angle B = angle P. The side of the smaller triangle that we do know is, 67.2 - 32 = 35.2 m. Now we can plug values into the law of sines.
35.2/sinB = x/sinA
sinA = (x/35.2)sinB
81.9/sinB = 67.2/sinA
sinA = (67.2/81.9)sinB
We can now equate both sinA equations and solve for x.
(x/35.2)sinB = (67.2/81.9)sinB
x/35.2 = 67.2/81.9
x = (35.2)(67.2/81.9)
x = 42.9 m
3.) We will make the assumption that the angle divided by the line inside the triangle is split in equal halves, therefore, both angles are the same. The angles at point D are angle D and and 180-D. It turns out that sinD = sin(180-D). If you do not believe this principle, test it out in a calculator. This will simplify our problems. We can simply use the law of sines once more.
(x+4)/sinE = 44.8/sinD
sinE = ((x+4)/44.8)sinD
35/sinE = 56/sinD
sinE = (35/56)sinD
((x+4)/44.8)sinD = (35/56)sinD
(x+4)/44.8 = 35/56
x+4 = (35/56)(44.8)
x = (35/56)(44.8) - 4
x = 24 m
4.) This problem is very similar to problem two, containing a parallel line that results in angles on the same side of the parallel line being equivalent.
45/sinθ = (13+2x)/sinθₓ
sinθ = (45/(13+2x))sinθₓ
5/sinθ = 3/sinθₓ
sinθ = (5/3)sinθₓ
(5/3)sinθₓ = ((45/(13+2x))sinθₓ
5/3 = 45/(13+2x)
13+2x = 27
2x = 14
x = 7m
5.) The area of a triangle is found using the formula, A = (1/2)b·h. We are already given the area of the triangle and the height of the triangle. The base of this triangle IS the hypotenuse, so solving for the base will answer this question.
A = (1/2)(b)(15) = 270
b = (270)(2/15)
b = 36 m
