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Semenov [28]
3 years ago
6

What’s the standard form of the line that passes through (7,-3) and has a y-intercept of 2?

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
First, let's solve in slope-intercept form since it's easier. After that, we can turn it into standard form.

Recall the format of slope-intercept form: y = mx + b

We know that the y-intercept is 2, so we can input it into our equation ('b' represents the y-intercept!)

y = mx + 2
In order to solve for the slope, input the coordinates (7, -3)

-3 = 7m + 2
-5 = 7m
m = -5/7

y = -5x/7+ 2
In order to turn it into standard form, just make sure 'x' and 'y' are on the same side:

y + 5x/7 = 2 is the standard form of the line

-T.B.
777dan777 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

(y-y)=m(x-x)

(y--3)=2(x-7)

y+3=2x-14

y+3+14=2x

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3 years ago
16 increased by twice a number is -24 what is the solution?
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Let x = the number.

"increased by" tells you we are adding.

"twice a number" tells you 2 times a number.

16 + 2x = - 24

Subtract 16 from both sides so that we have the variable on one sides and the constants on the other.

2x = - 24 - 16

2x = - 40

Divide by 2 to isolate the variable.

x = - 40/2 = - 20

Your solution is - 20.

To check your answer, plug in.

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3 years ago
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Therefore point P is located in the : Third and fourth quadrants

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