All categories

3 years ago

Factor by using the difference of squares method: 36x^4 - 4x^2

1 answer:

4 0

The difference of squares formula is a^2-b^2=(a+b)(a-b). a^2, in this case, is 36x^4, so we can say the square root(positive in this case) is 6x^2. This means that a is 6x^2. We can do this also to the b^2 part and get 4x^2=b^2 so b=2x. The difference of squares formula states that the answer is (6x^2+2x)(6x^2-2x), so the answer is D.

You might be interested in

The midpoint of RS¯¯¯¯¯¯¯ is M. Use the given endpoint R(23, 14) and midpoint M(13, 8) to find the coordinates of the other endp

Oksanka [162]

The coordinates of other endpoint S is (3, 2)

<h3><u>Solution:</u></h3>

Given that midpoint of RS is M

Given endpoint R(23, 14) and midpoint M(13, 8)

To find: coordinates of the other endpoint S

<em><u>The formula for midpoint is given as:</u></em>

For a line containing containing two points $(x_1, y_1)$ and $(x_2, y_2)$ midpoint is given as:

$m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here in this problem,

m(x, y) = (13, 8)

$(x_1, y_1) = (23, 14)\\\\(x_2, y_2) = ?$

Substituting the given values in above formula, we get

$(13,8)=\left(\frac{23+x_{2}}{2}, \frac{14+y_{2}}{2}\right)$

Comparing both the sides we get,

$\begin{aligned}&13=\frac{23+x_{2}}{2} \text { and } 8=\frac{14+y_{2}}{2}\\\\&26=23+x_{2} \text { and } 16=14+y_{2}\\\\&x_{2}=3 \text { and } y_{2}=2\end{aligned}$

Thus the coordinates of other endpoint S is (3, 2)

8 0

3 years ago

Solve for 2x^2-4x+5=6

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in your values
x = $\frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-1)} }{2(2)}$ Simplify
x = $\frac{4 \pm \sqrt{16 + 8} }{4}$ Simplify
x = $\frac{4 \pm 2\sqrt{6} }{4}$ Simplify by removing a 2 from every term
x = $\frac{2 \pm \sqrt{6} }{2}$ Simplify by taking the fraction apart
x = $\frac{2}{2} \pm \frac{ \sqrt{6} }{2}$ Change $\frac{2}{2}$ to 1
x = 1 $\pm \frac{ \sqrt{6} }{2}$ Simplify $\frac{ \sqrt{6} }{2}$ to $\sqrt{ \frac{3}{2} }$
x = 1 $\pm \sqrt{ \frac{3}{2} }$

4 0

3 years ago

The perimeter of a rectangular swimming pool is 154m.Its length is 2m more than twice its breadth. What are the length and bread

TiliK225 [7]

$P = 154\\a = 2b + 2$

a = ?; b = ?

$P = 2(a + b) = 2(2b + 2 + b) = 2(3b + 2) = 6b + 4$

$154 = 6b + 4\\6b = 154 - 4\\6b = 150\\b = 150 : 6\\b = 25$

$a = 2b + 2 = 2 * 25 + 2 = 50 + 2 = 52$

Answer: 25 and 52 m.

3 0

3 years ago

I need help with this

yawa3891 [41]

Answer:

Step-by-step explanation:

In the graph given, we can expect the x axis to be horizontal and the y axis to be vertical. This means that the arm span represents y and the height represents x.

Therefore, if a girl on her team is 63 inches tall, we can say that y=x+2, and since height is x, y = 63 + 2 = 65

6 0

3 years ago

54 + 81 = 9(6 +_) I need the help to answer my question

Otrada [13]

Answer:

Step-by-step explanation:

54+81=9(6+9)

9 times 9 equals 81

7 0

3 years ago

Read 2 more answers