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Neporo4naja [7]
3 years ago
13

What is the solution to this inequality ? 12x > 5 (x-2)

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0
12x>5(x-2)
12x>5x-10
12x-5x>-10
7x>-10
x>-10/7    or      (-10/7, +∞)

Answer:  x>-10/7    or    (-10/7 , +∞)
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Dan's car depreciates at a rate of 17% per year.
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68%

Step-by-step explanation:

17% × 4

68%

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3 years ago
Solve for r.<br><br> 27r = 783
Ksju [112]

Answer:29

Step-by-step explanation:

27r=783

   divide both sides by 27

 27r÷27=783÷27

         r=29

6 0
3 years ago
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Anne's potato salad recipe requires one pound of potatoes for every four people served. How many pounds of potatoes will Anne ne
Ierofanga [76]

Answer:

3.5 pounds for 14 people

Step-by-step explanation:

Given

1 pound = 4 people

Required

Determine the pounds for 14 people

Represent this with x; so, we have:

1\ pound = 4\ people

x = 14\ people

Cross Multiply

x * 4 = 1 * 14

4x = 14

Solve for x

x = 14/4

x = 3.5

<em>Hence, 3.5 pounds for 14 people</em>

6 0
2 years ago
Help plssssssssssssssssss
Evgesh-ka [11]

Answer:

72

Step-by-step explanation:

6 0
3 years ago
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A loaded 8-sided die is loaded so that the number 4 occurs 3/10 of the time while the other numbers occur with equal frequency.
Law Incorporation [45]

Answer:

4.4

Step-by-step explanation:

The sum of the probabilities of all possible outcomes is 1.

As the die is loaded so that the number 4 occurs 3/10 of the time, and the other numbers occur with equal frequency, then the probability of numbers 1, 2, 3, 5, 6, 7 and 8 being rolled is 1/10.

Create a probability distribution table for X, where X is the score on the loaded 8-sided die:

\begin{array}{ | c | c | c | c | c | c | c | c | c |}\cline{1-9}x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\\cline{1-9} & & & & & & & &\\ \text{P}(X=x) & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{3}{10} & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{1}{10}\\& & & & & & & &\\\cline{1-9}\end{array}

Add a product row and a totals column:

\begin{array}{ | c | c | c | c | c | c | c | c | c | c |}\cline{1-10}x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 &\text{Total} \\ \cline{1-10} &&&&&&&&& \\ \text{P}(X=x) & \frac{1}{10} & \frac{1}{10} & \frac{1}{10} & \frac{3}{10} & \frac{1}{10} & \frac{1}{10} & \frac{1}{10} & \frac{1}{10} & 1\\ &&&&&&&&&\\ \cline{1-10} &&&&&&&&&\\\text{Product} & \frac{1}{10} & \frac{2}{10} & \frac{3}{10} & \frac{12}{10} & \frac{5}{10} & \frac{6}{10} & \frac{7}{10} & \frac{8}{10} & \frac{44}{10} \\ &&&&&&&&&\\\cline{1-10}\end{array}

(The Product is row is the product of the <u>score on the die</u> and <u>its probability</u>).

The expected value (EV) is the sum of the product of each outcome and its probability.  

Therefore, the expected value (EV) of this die is 44/10 = 4.4

6 0
2 years ago
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