5 is common factor
also x
reverse distributive
ab+ac=a(b+c)
5x(x)+5x(4)=5x(x+4)
last one
Answer:
Kindly check explanation
Step-by-step explanation:
Given that:
Cost per bracelet = 1.50
Cost per necklace = 2.25
Let :
number of necklace = n
Number of bracelet = b
Cost equation C ;
C = 1.5b + 2.25n
Number of necklace that could be sold for exactly $12
5 necklaces and 1 bracelet :
1.5 + 2.25(5) = 12.75
•2 necklaces and 5 bracelets:
1.5(5) + 2.25(2) = 12
• 3 necklaces and 3 bracelets
1.5(3) + 2.25(3) = 11.25
• 4 necklaces and 2 bracelets
1.5(2) + 2.25(4) = 12
• 3 necklaces and 5 bracelets
1.5(5) + 2.25(3) = 14.25
• 6 necklaces and no bracelets •
1.5(0) + 2.25(6) = 13.5
No necklaces and 8 bracelets
1.5(8) + 2.25(0) = 12
Amount charged per Tshirt = c
Setup fee = $40
Number of students in drama club = 21
Total cost of order = $187
Calculate C ;
Total order cost = set up fee + (cost per shirt * number of shirts)
Total order cost = 40 + 21c
187 = 40 + 21c
187 - 40 = 21c
147 = 21c
c = 147 / 21
C = 7
Hence cost per shirt = $7
Answer:
![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
Step-by-step explanation:
This was right on my test. I completely guessed so I don't really have an explanation.
Answer:
1). g(-9) = -81.914
2). Last option
Step-by-step explanation:
1). f(x) = x²
For x = -9
f(-9) = (-9)² = 81
g(x) = 
g(-9) = ![\frac{32}{[2(-9)-17]}](https://tex.z-dn.net/?f=%5Cfrac%7B32%7D%7B%5B2%28-9%29-17%5D%7D)
= 
= -
(g - f)(-9) = g(-9) - f(-9)
= 
= 
= 
= -81.914
2). The relation is not a function because this function doesn't passes a vertical line test.
Last option will be the answer.
Answer:

Step-by-step explanation:
The Universal Set, n(U)=2092


Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted
from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects, 