Need help on number six

What times 25 equals 13107200?

leva [86]

Answer:

524,288

Step-by-step explanation:

3 0

3 years ago

If the student has already read 2525 of the pages, how long will it take them to read the rest of the book? _____ minutes Your a

Alja [10]

The number of pages the student can read in a minute is an illustration of rates.

The time left to complete the whole book is 90 minutes

From the complete question, the student's rate is:

$\mathbf{Rate = 50\ pages/hr}$

The number of pages is:

$\mathbf{Total = 100\ pages}$

First, we calculate the time to read the whole book

$\mathbf{Total\ Time = \frac{Total\ pages}{Rate}}$

$\mathbf{Total\ Time = \frac{100\ pages}{50\ pages/ hr}}$

$\mathbf{Total\ Time = 2\ hours}$

The number of the student has read is:

$\mathbf{Pages = 25}$

Next, we calculate the time spent on the 25 pages

$\mathbf{Time\ Spent = \frac{Pages}{Rate}}$

$\mathbf{Time\ Spent = \frac{25\ pages}{50\ pages/hr}}$

$\mathbf{Time\ Spent = 0.5\ hr}$

Convert to minutes

$\mathbf{Time\ Spent = 30\ minutes}$

So, the time left is:

$\mathbf{Time\ Left = Total\ Time - Time\ Spent}$

This gives

$\mathbf{Time\ Left = 2\ hours- 30\ minutes}$

$\mathbf{Time\ Left = 1\ hour, 30\ minutes}$

Convert to minutes

$\mathbf{Time\ Left = 90\ minutes}$

Hence, the time left is 90 minutes

Read more about rates at:

brainly.com/question/18065083

5 0

3 years ago

What is the length of a pencil?

victus00 [196]

It depends on what kind of pencil it is.

3 0

3 years ago

Read 2 more answers

Letv⃗ 1=⎡⎣⎢012⎤⎦⎥,v⃗ 2=⎡⎣⎢1−20⎤⎦⎥,v⃗ 3=⎡⎣⎢30−1⎤⎦⎥be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−3, λ2=2

dem82 [27]

What is this????????????????????

6 0

3 years ago

The output of a chemical process is continually monitored to ensure that the concentration remains within acceptable limits. Whe

marissa [1.9K]

Answer:

a) 0.31 = 31%

b) 0.03 = 3%

c) 0.36 = 36%

d) 2 times

Step-by-step explanation:

If $F_X(x)$ is the cumulative distribution function of the random variable X, then by definition the probability P of the random variable is given by

$P(X \leq x) = F_X(x)$

If additionally the random variable is discrete (only has non-negative integers as outcomes as is the case in this problem) then

$P(X=a)=F_X(a)-\lim_{x \to a^-}F_X(x)$

a)

We are looking for P(X<2)

$P(X < 2) = P(X\leq 2)-P(X=2)=F_X(2)-\lim_{x \to 2^-}F_X(x)=0.84-0.53=0.31$

b)

In this case we want P(X>3)

$P(X >3) = 1-P(X\leq 3)=1-F_X(3)=1-0.97=0.03$

c)

Now, we are interested in P(X=1)

$P(X =1) =F_X(1)-\lim_{x \to 1^-}F_X(x)=0.53-0.17=0.36$

d)

The expected number of times that the process is recalibrated during the week is the expected value of the probability distribution:

P(X=1)+2P(X=2)+...+nP(X=n)+...

But it is easy to see that P(X=n) = 0 if n is an integer >4

So, the expected value is

P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)

We already have P(X=1) and P(X=2). Let's compute the rest

$P(X =3) =F_X(3)-\lim_{x \to 3^-}F_X(x)=0.97-0.84=0.13$

$P(X =4) =F_X(4)-\lim_{x \to 4^-}F_X(x)=1-0.97=0.03$

and the expected value is

0.36 + 2*0.53+3*0.13+4*0.03= 1.93 = 2 times rounding to the nearest integer.

8 0

4 years ago